Answer:
Step-by-step explanation:
From the picture attached,
a). Triangle in the figure is ΔBCF
b). Since, 
and 
are the parallel lines and m is a transversal line,
m∠FBC = m∠BFG [Alternate interior angles]
Since, and are the parallel lines and n is a transversal line,
m∠BCF = m∠CFE [Alternate interior angles]
By triangle sum theorem in ΔBCF
m∠FBC + m∠BCF + m∠BFC = 180°
From the properties given above,
m∠BFG + m∠CFE + m∠BFC = 180°
m∠GFE = 180°
Therefore, angle GFE is the straight angle that will be useful in proving that the sum of the measures of the interior angles of the triangle is 180°.
Answer:
hope this helps you out good luck
Answer:
3x+2y
Step-by-step explanation:
Find the rectangles attached
Area of a rectangle = Length * Width
A = A1+A2
given
A = 30cm²
A1 = 3 * x
A1 = 3x
A2 = 2*y
A2 = 2y
Substitute
30 = 3x+2y
Hence the required equation is 3x+2y = 30
First of all, you have to understand
<span> is a square-root function.
</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative.
</span>
In other words, for any square-root function
and any input
in the domain of
(except for its endpoint), we know that this equality holds:
Let's take
<span>as an example.
</span>
The domain of
is all real numbers such that
. Since
is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach
<span>from the left).
</span>
<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value:
</span>
In conclusion, the equality
holds for any square-root function
and any real number
in the domain of
e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>
The input
, is within the domain of
<span>.
</span>
Therefore, in order to find
we can simply evaluate
at
<span>.
</span>
