Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,
Taking last two ratio,
Putting the value of BC , AC ,∠A,∠B
≈734.106 miles
Therefore they are 734.106 miles apart.
1/2(2x+6)
Substitute the one half to both of the numbers inside the parentheses.
1/2*2 is one which would just be x
1/2*6 is three
X+3
Answer:
B. Train B
Step-by-step explanation:
We are told that Milford and Pinkerton is 300 miles away.
Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.
Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.
Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.
Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.
