There would be 9 birds left. 10-1=9
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
You add/subtract complex numbers simply by adding/subtracting real parts and imaginary parts.
So, the real part of this sum is the sum of the real parts:
And the imaginary part of this sum is the sum of the imaginary parts:
So, you have
5. . 1
---- - -----
6. . 2
5. . 3
----- - -----
6. . 6
5-3
-------
6
2
-----
6
= 1/3
B
Answer: g=2
Step-by-step explanation:5.5g+3=2.5g+9
We move all terms to the left:
5.5g+3-(2.5g+9)=0
We get rid of parentheses
5.5g-2.5g-9+3=0
We add all the numbers together, and all the variables
3g-6=0
We move all terms containing g to the left, all other terms to the right
3g=6
g=6/3
g=2
