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Romashka [77]
3 years ago
5

Manny makes dinner using 1 box of pasta and 1jar of sauce .If pasta is sold in oackage if 6 boxes and sauce is sold in in packag

es of 3 jjara what is the least number of dinners that manny can make without any supplies leftover
Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

The least number of dinners that manny can make without any supplies leftover is 6 dinners

Step-by-step explanation:

Dinner = 1 box of pasta + 1jar of sauce

pasta is sold in package of 6 boxes

sauce is sold in in packages of 3

jars

what is the least number of dinners that manny can make without any supplies leftover?

Find the lowest common multiple of 6 boxes and 3 jars

6 boxes = 6, 12, 18, 24, 30, 36, 42,48

3 jars = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

The lowest common multiple of 6 boxes and 3 jars = 6

The least number of dinners that manny can make without any supplies leftover is 6 dinners

Using:

Pasta = 6 dinners / 6 boxes

= 1 package

Pasta = 1 package

Sauce = 6 dinners / 3 jars

= 2 package

Sauce = 2 package

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4 years ago
Which shows the following expression using positive exponents?
Hitman42 [59]

Answer:

1. option B is correct i.e., \frac{-3a^{7}b^3b^1}{15a^{2}}

2. option D is correct i.e., \frac{a^3b^4}{ab^2}.

3. option B is correct i.e.,  \frac{n^{10}}{16m^{6}}.

Step-by-step explanation:

1. Since the given equation is:

\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}

As we know that a^{-x}=\frac{1}{a^x}

So, the given equation can be represented as:

\frac{-3a^{7}b^3b^1}{15a^{2}}


2. Given equation is:

\frac{a^3b^{-2}}{ab^{-4}}

As we know that a^{-x}=\frac{1}{a^x}

so the given equation can be represented as:

\frac{a^3b^4}{ab^2}.


3.  Given equation is:

(\frac{4mn}{m^{-2}n^6})^{-2}

by using the properties a^{-x}=\frac{1}{a^x},

and a^x\times a^y=a^{x+y}

(\frac{4mn}{m^{-2}n^6})^{-2}

= (\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}

= (\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}

= (\frac{4n^{-5}}{m^{-3}})^{-2}

= \frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}

= \frac{n^{10}}{16m^{6}}.

which is option B.

5 0
3 years ago
Read 2 more answers
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