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ale4655 [162]
3 years ago
5

Can i have help plz i rally need it

Mathematics
1 answer:
marin [14]3 years ago
6 0
The answer is D. 4:3
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then 

h( \frac{5}{4} )=-6\cdot  (\frac{5}{4} )^2+15\cdot \frac{5}{4} +2= \frac{91}{8} =11.375

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</span><span>The projectile initially launched at time t=0, so the initial height is h(0)=2 m</span>


6 0
4 years ago
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