Answer:
The total amount after 3 years is = $ 2054.10
Explanation:
Given data
Principal Amount (P) = $ 1800
Rate of interest (R) = 4.5 %
Thus the total amount after 3 years compounded annually is given by the formula = P × ![[1 +\frac{R}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7BR%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 1800 × ![[1 +\frac{4.5}{100} ]^{3}](https://tex.z-dn.net/?f=%5B1%20%2B%5Cfrac%7B4.5%7D%7B100%7D%20%20%5D%5E%7B3%7D)
⇒ 2054.10
Thus the total amount after 3 years is = $ 2054.10
Compound interest earned in three years = 2054.10 - 1800 = $ 254.10
This question is incomplete, but I can do it for you, considering the equation to be *In its most famous form*:
A+B⇒C+D
A and B here are the reactants, while C and D are the products.
The reactants are generally the input materials in the beginning of any chemical reactions and they usually, if not always, are on the left hand side of the chemical equation. While the products are on the right hand side and are the final output of the chemical reaction.
Hope this helps.
Answer:
a) v = 0.7071 v₀, b) v= v₀, c) v = 0.577 v₀, d) v = 1.41 v₀, e) v = 0.447 v₀
Explanation:
The speed of a wave along an eta string given by the expression
v = 
where T is the tension of the string and μ is linear density
a) the mass of the cable is double
m = 2m₀
let's find the new linear density
μ = m / l
iinitial density
μ₀ = m₀ / l
final density
μ = 2m₀ / lo
μ = 2 μ₀
we substitute in the equation for the velocity
initial v₀ =
with the new dough
v =
v = 1 /√2 \sqrt{ \frac{T_o}{ \mu_o} }
v = 1 /√2 v₀
v = 0.7071 v₀
b) we double the length of the cable
If the cable also increases its mass, the relationship is maintained
μ = μ₀
in this case the speed does not change
c) the cable l = l₀ and m = 3m₀
we look for the density
μ = 3m₀ / l₀
μ = 3 m₀/l₀
μ = 3 μ₀
v =
v = 1 /√3 v₀
v = 0.577 v₀
d) l = 2l₀
μ = m₀ / 2l₀
μ = μ₀/ 2
v =
v = √2 v₀
v = 1.41 v₀
e) m = 10m₀ and l = 2l₀
we look for the density
μ = 10 m₀/2l₀
μ = 5 μ₀
we look for speed
v =
v = 1 /√5 v₀
v = 0.447 v₀