According to another source this is what I got
<span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m )
</span>Hope it helps
Answer:
The acceleration will also double
Explanation:
F = m*a
a = F/m
plugging in sample numbers to prove
a= 100/4 = 25
a = 200/4 = 50
Answer:
The Required pressure for this situation is P= 735000Pa
Explanation:
In Determining the required pressure in this situation we use two equations
First one is
F = mg = (ρhA)g
And Second one is
P = 
= (ρhAg)/A Where P is pressure
We get
P = ρhg
since g = 9.8 m/s and h is given that is 75m and ρ = 
so
P = (9.8 m/s)()(75) we get
P = 735000 Pa
Answer:
426136363636.36365 Bq
Explanation:
Grays = 12
Mass = 2 kg
Time = 880
Energy = 0.4 MeV
Activity is given by
The activity N//t of the radioactive source is 426136363636.36365 Bq
Answer:
Explanation:
a )
Amplitude A = 14 mm , angular frequency ω = 2π / T
= 2π / .5
ω = 4π rad /s
φ₀ = initial phase
Putting the given values in the equation
14 = 25 cos(ωt + φ₀ )
14/25 = cosφ₀
φ₀ = 56 degree
x(t) = 25cos(4πt + 56° )
b )
maximum velocity = ω A
= 4π x 25
100 x 3.14 mm /s
= 314 mm /s
At x = 0 ( equilibrium position or middle point , this velocity is achieved. )
maximun acceleration = ω² A
= 16π² x A
= 16 x 3.14² x 25
= 3943.84 mm / s²
3.9 m / s²
It occurs at x = A or at extreme position.
