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Ierofanga [76]
3 years ago
6

2. Which of the following is accurate when discussing specific neat?

Physics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

The specific heat of a gas may be measured at constant pressure. - is accurate when discussing specific heat.

Explanation:

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A long distance running is running the 10000 m race. He runs the first 2000 m in 5 minutes, the next 5000 m in 14 minutes and th
Shtirlitz [24]
This kind of problems are solved by dividing total distance with the total time necessary for him to get from the start to the finish line. In this case, total distance is 10000m and the total time is the sum of the times that were given (which is 26 minutes, or 1560 seconds). Dividing these two numbers, the average speed is:
\frac{1000m}{1560s}  = 6.41 \frac{m}{s}
8 0
3 years ago
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1. A plane travels a distance of 500
Yanka [14]

Answer:

Option C, 139 m/s

Explanation:

s = d/t

s = 500*10^3/3600

s = 138.8 = 139 m/s

5 0
4 years ago
The stemplot below shows the heights (in inches) of students in a class.
alexandr1967 [171]

Answer:

51

Explanation:

Just looked at the chart

3 0
3 years ago
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1. A 0.250 kg baseball sits on the ledge of a window in Treadwell hall. If the ball has 18.5
Lunna [17]

Answer:

h = 7.54 m

t = 1.24 s

Explanation:

1.Let g = 9.81 m/s2 is the gravitational acceleration. Since the formula for potential energy is:

E_p = mgh

where m = 0.25 is the ball mass and h is the height. We can solve for h

h = \frac{E_p}{mg} = \frac{18.5}{0.25*9.81} = 7.54m

2. The time it take for the ball to reach a distance of 7.54m with a gravitational acceleration of 9.81m/s2:

h = \frac{gt^2}{2}

t^2 = \frac{2h}{g} = \frac{2*7.54}{9.81} = 1.54

t = \sqrt{1.54} = 1.24 s

4 0
3 years ago
A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find
pshichka [43]

Answer:

0.050 m

Explanation:

The strength of the magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0=4\pi \cdot 10^{-7} H/m is the vacuum permeability

I is the current in the wire

r is the distance from the wire

And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.

In this problem, we have:

I=1.41 A (current in the wire)

B=5.61\mu T=5.61\cdot 10^{-6} T (strength of magnetic field)

Solving  for r, we find the distance  from the wire:

r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m

4 0
3 years ago
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