Because during a phase change nothing really happens. Before a phase change, energy and temperature will increase or decrease as well as after.
Answer:
None of the wavelength is in the visible range
Explanation:
Constructive interference of the reflected waves for different wavelengths can be estimated using:
λ
= 2nd/m
where m is 1,2,3, ...
Therefore:
m=1, λ
= 750 nm
m=2, λ
= 750/2 = 375 nm
The limits of eye's sensitivity is between 430 nm and 690 nm. Beyond this range, the eye's sensitivity drops to approximately 1% of its maximum value.
Answer:
It requires <u>1.9 seconds</u> to reach maximum height.
Explanation:
As per given question,
Initial velocity (U) =19 m/s
Final velocity (V) = 0 m/s

Maximum height = S
Time taken is "t"
<u>Calculating time taken to reach maximum height:</u>
We know that time taken to reach the maximum height is calculated by using the formula V = U + at
Substitute the given values in the above equation.
Final velocity is “0” as there is no velocity at the maximum height.



t = 1.9 seconds.
The time taken to reach maximum height is <u>1.9</u> seconds.
<u>Calculating maximum height</u>:

Solving the equation we will get the value of S

-361 = -20S
Negative sign cancel both the sides.

S = 18.05 m
Maximum height is 18.05 m .
T = 4.25 ms = 4 x 10⁻³ s, the time for rebound
v₁ = 25.5 m/s, the impacting velocty
v₂ = -19.5 m/s, the rebounding velocity (n the opposite directon)
The change in velocity is
v₂ - v₁ = - (25.5+19.5) = -45 m/s
The acceleration is
a = (-45 m/s)/(4 s) = -11.25 m/s²
The negative sign indicates that the final velocity is opposiye to the impact velocty.
Answer: The magnitude of the acceleration is 11.25 m/s²
Answer:
Explanation:
Givens
vi = 0
a = 9.81
d = 4.50 m
vf = ?
Formula
vf^2 = vi^2 + 2 * a * d
Solution
Substitute the knowns into the formula
vf^2 =0 + 2 * 9.81 * 4.50
vf^2 = 88.29 Take the square root of both sides.
sqrt(vf^2) = sqrt(88.29)
vf = 9.40 m/s