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HACTEHA [7]
3 years ago
8

isotopes of an element differ in the composition of the nucleus. The varying numbers of ____ cause the _____ of each isotope to

also vary.
Physics
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:

The answer is neutrons and mass number

Explanation:

Leni [432]3 years ago
5 0

Answer:

I have this same question on usa test prep the answer is nuetrons and mass number

Explanation:

You might be interested in
Why is temperature constant during a phase change?
shutvik [7]
Because during a phase change nothing really happens. Before a phase change, energy and temperature will increase or decrease as well as after.
8 0
3 years ago
For what visible wavelengths of light do the reflected waves interfere constructively? The range of wavelength of visible light
Otrada [13]

Answer:

None of the wavelength is in the visible range

Explanation:

Constructive interference of the reflected waves for different wavelengths can be estimated using:

λ_{m} = 2nd/m

where m is 1,2,3, ...

Therefore:

m=1, λ_{1} = 750 nm

m=2, λ_{1} = 750/2 = 375 nm

The limits of eye's sensitivity is between 430 nm and 690 nm. Beyond this range, the eye's sensitivity drops to approximately 1% of its maximum value.

7 0
4 years ago
if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
A 49.5 gram super ball traveling at 25.5 m/s bounces off a brick wall and rebounds at 19.5 m/s. a high-speed camera records this
OLga [1]
T = 4.25 ms = 4 x 10⁻³ s, the time for rebound
v₁ = 25.5 m/s, the impacting velocty
v₂ = -19.5 m/s, the rebounding velocity (n the opposite directon)

The change in velocity is
v₂ - v₁ = - (25.5+19.5) = -45 m/s

The acceleration is
a = (-45 m/s)/(4 s) = -11.25 m/s²
The negative sign indicates that the final velocity is opposiye to the impact velocty.

Answer: The magnitude of the acceleration is 11.25 m/s²
8 0
3 years ago
6.
Vikentia [17]

Answer:

Explanation:

Givens

vi = 0

a = 9.81

d = 4.50 m

vf = ?

Formula

vf^2 = vi^2 + 2 * a * d

Solution

Substitute the knowns into the formula

vf^2 =0 +  2 * 9.81 * 4.50

vf^2 = 88.29                          Take the square root of both sides.

sqrt(vf^2) = sqrt(88.29)    

vf = 9.40 m/s

3 0
3 years ago
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