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3 years ago

The energy of a photon of light is proportional to its frequency and proportional to its wavelength.

Physics

1 answer:

icang [17]3 years ago

6 0

Answer:

D) directly, inversely

Explanation:

The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.

Frequency is the number of waves that passes through a point per unit of time.

Wavelength is the is the distance between successive crests or troughs on a wave.

Mathematically, frequency is related to wavelength and velocity using;

Energy = h x f

where h is the Planck's constant

f is the frequency

Since c = f ∧

where f is the frequency of the wave

∧ is the wavelength of the wave

c is the speed of light

So;

f = c/∧

Therefore;

E = $\frac{h c}{wavelength}$

From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.

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2 years ago

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<h2>~Solution :-</h2>

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2 years ago

A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 starts from rest at t = 0. The wheel has

irga5000 [103]

Answer:

The total linear acceleration is approximately 0.246 meters per square second.

Explanation:

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$a = \sqrt{a_{r}^{2}+a_{t}^{2}}$ (3)

Where:

$r$ - Radius of the wheel, in meters.

$\omega$ - Angular speed, in radians per second.

$\alpha$ - Angular acceleration, in radians per square second.

Given that wheel accelerates uniformly, we use the following kinematic equation:

$\omega = \omega_{o}+ \alpha\cdot t$ (4)

Where:

$\omega_{o}$ - Initial angular speed, in radians per second.

$t$ - Time, in seconds.

If we know that $r = 0.1\,m$ , $\alpha = 2\,\frac{rad}{s^{2}}$ , $\omega_{o} = 0\,\frac{rad}{s}$ and $t = 0.60\,s$ , then the total linear acceleration is:

$\omega = \omega_{o}+ \alpha\cdot t$

$\omega = 1.2\,\frac{rad}{s}$

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$a_{t} = 0.2\,\frac{m}{s^{2}}$

$a = \sqrt{a_{r}^{2}+a_{t}^{2}}$

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3 years ago

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olga55 [171]

Answer:

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3 years ago

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The energy of a photon of light is proportional to its frequency and proportional to its wavelength.