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xxMikexx [17]
2 years ago
9

The energy of a photon of light is __________ proportional to its frequency and __________ proportional to its wavelength.

Physics
1 answer:
icang [17]2 years ago
6 0

Answer:

D) directly, inversely

Explanation:

The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.

Frequency is the number of waves that passes through a point per unit of time.

Wavelength is the is the distance between successive crests or troughs on a wave.

 Mathematically, frequency is related to wavelength and velocity using;

             Energy   =  h x f

                      where h is the Planck's constant

                                  f is the frequency

         

                   Since c  = f ∧

where f is the frequency of the wave

           ∧ is the wavelength of the wave

           c is the speed of light

So;

                 f  = c/∧

  Therefore;

                E  = \frac{h c}{wavelength}

From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.

           

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The potential energy of a negative charge moved from point A to point B will increase.A negative charge moved from point A to po
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<em>The K.E from A to B won't increase...</em>

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That is the reason there is no effect on net K.E when moving from a potential to same potential over and over (A to C).

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5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ
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v= 1.71 m/s

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3 0
3 years ago
8.) If a car moving at 50km/h skids 15m with locked brakes, how far does the same car moving at 100km/h
pantera1 [17]

(8) A car starting with a speed <em>v</em> skids to a stop over a distance <em>d</em>, which means the brakes apply an acceleration <em>a</em> such that

0² - <em>v</em>² = 2 <em>a</em> <em>d</em> → <em>a</em> = - <em>v</em>² / (2<em>d</em>)

Then the car comes to rest over a distance of

<em>d</em> = - <em>v</em>² / (2<em>a</em>)

Doubling the starting speed gives

- (2<em>v</em>)² / (2<em>a</em>) = - 4<em>v</em>² / (2<em>a</em>) = 4<em>d</em>

so the distance traveled is quadrupled, and it would move a distance of 4 • 15 m = 60 m.

Alternatively, you can explicitly solve for the acceleration, then for the distance:

A car starting at 50 km/h ≈ 13.9 m/s skids to a stop in 15 m, so locked brakes apply an acceleration <em>a</em> such that

0² - (13.9 m/s)² = 2 <em>a</em> (15 m) → <em>a</em> ≈ -6.43 m/s²

So the same car starting at 100 km/h ≈ 27.8 m/s skids to stop over a distance <em>d</em> such that

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(9) Pushing the lever down 1.2 m with a force of 50 N amounts to doing (1.2 m) (50 N) = 60 J of work. So the load on the other end receives 60 J of potential energy. If the acceleration due to gravity is taken to be approximately 10 m/s², then the load has a mass <em>m</em> such that

60 J = <em>m g h</em>

where <em>g</em> = 10 m/s² and <em>h</em> is the height it is lifted, 1.2 m. Solving for <em>m</em> gives

<em>m</em> = (60 J) / ((10 m/s²) (1.2 m)) = 5 kg

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