A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
e given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. Show work. y=-16x^2+200x+82
1 answer:
Answer:
Step-by-step explanation:
y=-16x^2+200x+82
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Answer:
6x=54
Step-by-step explanation:
3x - {7-x} =29
open bracket
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collect like terms and equate
4x =29 +7
4x = 36
divide both sides by 4
x = 9
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6x= 54
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