A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
e given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. Show work. y=-16x^2+200x+82
1 answer:
Answer:
Step-by-step explanation:
y=-16x^2+200x+82
You might be interested in
Answer:
6/20 can I get brainliest pleast
Step-by-step explanation:
there is a chance that the teacher will pick a student without brown eyes 6/20 times
Answer:
The answer is x=1/2 or x=0.5
Answer: 5n + 13
Step-by-step explanation:
123454321\67891019876\123456789101987654321
Answer:
1814400
Step-by-step explanation:
