A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
e given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. Show work. y=-16x^2+200x+82
1 answer:
Answer:
Step-by-step explanation:
y=-16x^2+200x+82
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