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Nadusha1986 [10]
3 years ago
11

In a situation where the sample size was 28 while the population standard deviation was increased, what would be the impact on t

he confidence interval?
A) It would become narrower due to using the t distribution
B) It would widen with more values
C) It would become wider due to using the z distribution
D) It would become wider with more dispersion in values
Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

C; It would become wider due to using the z-distribution

Step-by-step explanation:

Mathematically, we go on to look at the formula for confidence interval calculations here

The formula involves multiplying z by the s

which is the z-value and the standard deviation

Increasing the standard deviation value means we are increasing the product of multiplying z and s

This means that we are getting a larger value for the multiplication

Thus, we now have a wider confidence interval value as a result of a larger product

So this means that the CI would become wider due to the usage of the z-distribution

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Nuetrik [128]

Answer:

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Step-by-step explanation:

We need to rewrite the expression (3^\frac{2}{3})^\frac{1}{6} with a rational exponent as a radical expression.

The expression given is:

(3^\frac{2}{3})^\frac{1}{6}

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