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MissTica
3 years ago
15

Your classmate is unsure about how to use side lengths

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0

Answer:

you look at the lengths some triagles have small parallel lines anè or two of them to determine if they are equal or different from one another

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I need help with this problem please?
user100 [1]

Answer:

Step-by-step explanation:

If ΔABC ~ ΔPQR

\frac{PQ}{AB} =\frac{QR}{BC} = \frac{RP}{CA}

or

\frac{AB}{PQ} =\frac{BC}{QR} =\frac{CA}{RP}

3 0
3 years ago
Hey can someone please help me with just number 13 ?
Fudgin [204]
THE ANSWER IS B! YOUR WELCOME!
7 0
3 years ago
The maximum weight on a roller coaster is 400 pounds. If your friend weighs 120 pounds, what is the most that you can weigh so y
wolverine [178]
The maximum weight on a roller coaster is 400 pounds (Max = 400).
If your friend weighs 120 pounds (y = 120), what is the most you can weigh so you can ride together (x + y < 400).

x + 120 <_ 400.
y = 120

Subtract 120 from both sides.

x <_ 280.

You can weigh at most 280 pounds (x <_ 280).

I  hope this helps!
7 0
3 years ago
Please help me answer these 2 questions with a FULL explanation so I know how to do the rest myself. Giving brainliest.
sveticcg [70]

Answer to 1:

\frac{x^3}{2y^25}

First thing you want to do is combine like terms on the bottom. Since it's multiplication, all you have to do is add the exponents. So for x you'd get x raised to the -9 power and for y you'd get 2y raised to the power of 7

Second thing is the numerator of the fraction. Since this is raising what is inside the paranthesis to a power, you must multiply this power by the powers of x and y, respectively. You should get x raised to the power of -6 and y raised to the power of -18

Here's where it gets complicated. to rationalize the problem, you must add parts from the numerator and denominator or vice versa. You cannot have any negative exponents anywhere in the fraction.  So that means for x you have to add 9 to the x on the top to cancel out the -6 and rationalize the remaining x's. You should end up with x^3.

For y, you work the opposite way. Since the negatives are only on the top, you simply add 18 to the bottom y's and it remains rationalized.

If done correctly this should come out to x^3/2y^25

Answer to 2:

(x^20y^12)/256

First thing you can do on this one is to cancel out the x^0s. Anything to the power of 0 equals one so only the coefficients will remain. Multiply those together and you'll get 4.

Next you will rationalize the ys. Add the bottom 3 to the top to cancel out the denominator and you're left with y^-3. Leave it like this for now.

Now is the difficult part. You must take everything that is inside the parenthesis to the power of -4. That includes the coefficients and the exponents. 4^-4 = 1/256. This means that you now must move the coefficients to the bottom. You should currently have y^-3/(256x^5).

Now take the exponents to the power using the same rules as question 1. -3*-4 = 12 and 5*-4 = -20. You should now have y^12/(256x^-20)

Lastly, we must rationalize the denominator. To do so, move the x^-20 to the numerator and make the exponent positive. After doing this, you have the answer: (x^20y^12)/256

3 0
2 years ago
Can a triangle be drawn with the following side lengths? Why or why not?
Ghella [55]
Yes, because it still have 3 sides.
4 0
2 years ago
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