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krek1111 [17]
3 years ago
12

Can anyone tell me what the answer please

Mathematics
1 answer:
Tasya [4]3 years ago
3 0

What you're looking at in this image are two alternate exterior angles.

Alternate exterior angles, are, essentially, exterior angles of a transversal that runs through two parallel lines. These angles are on alternating sides. These angles, assuming the lines are parallel, must be equal.

There's a proof behind why these angles are equal, but I won't bore you with the specifics as the question doesn't require it.

So - we know that these two angles must be equal to prove that the lines A and B are parallel. Knowing this, we can write an equation:

5x + 20 = 3x + 60

<u>Subtract 20 from both sides:</u>

5x + 20 - 20 = 3x + 60 - 20

5x = 3x + 40

<u>Subtract 3x from both sides:</u>

5x - 3x = 3x - 3x + 40

2x = 40

x = 20

If you have any questions on how I got to the answer, just ask!

- breezyツ

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ozzi

Answer:

line of best fit

Step-by-step explanation:

line of best fit is NOT a method for solving a quadratic equation.

Rest of all the methods are used for solving a quadratic equation.

3 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
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Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
If parallelogram JKLM is rotated 270° counterclockwise around the origin, what are the coordinates of the endpoints of the side
allochka39001 [22]
No graph, so cannot be precise.
But you can apply rotation 270 CCW = rotation -90 CCW

r_[90] : (x,y) -> (y,-x)
7 0
2 years ago
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Kazeer [188]

3y+7=31

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24 divided by 3 is 8

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2 years ago
What is the slope of the line that passes through the points (2, 8) and (6, 12)?
algol13
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6 0
3 years ago
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