Answer:
line of best fit
Step-by-step explanation:
line of best fit is NOT a method for solving a quadratic equation.
Rest of all the methods are used for solving a quadratic equation.
Answer:
71.123 mph ≤ μ ≤ 77.277 mph
Step-by-step explanation:
Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:
≤ μ ≤ 
Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and
is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.
the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.
So, if we replace m by 74.2, s by 5.3083, n by 10 and
by 1.8331, we get that the 90% confidence interval for the mean speed is:
≤ μ ≤ 
74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077
71.123 ≤ μ ≤ 77.277
No graph, so cannot be precise.
But you can apply rotation 270 CCW = rotation -90 CCW
r_[90] : (x,y) -> (y,-x)
3y+7=31
3y=24 (we subtracted 7 from both sides)
24 divided by 3 is 8
Y=8
The answer is C. The "ruse over run" as most might say is 4/4 which simplifys to 1, so it's up one over one.