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stiv31 [10]
3 years ago
12

How would you solve this?

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
6 0
I’m sorry but I did not understand the question
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Mechanism with a small activation energy or one with large activation energy​
tangare [24]

Answer:

Rate depends on the rate constant. The rate constant depends on temperature and activation energy. If you have lower activation energy the rate will be higher. This is why catalysts are added since catalysts provide an alternate pathway that requires lower activation energy and catalysts are added to increase the rate of reaction.

Explanation:

This is only the answer if you were asking:

"Which corresponds to the faster rate: a mechanism with a small activation energy or one with a large activation energy?"

Thats what I understood about your question.

8 0
4 years ago
7. predict how atoms such as c, h, o, and n share electrons in a covalent bond, the role of electronegativity, and the potential
Lena [83]

The atoms C,H,O and N becomes more electronegative as the periodic table's right side and top get increasingly electronegative as you move down it. A hydrogen bond needs to share elements with hydrogen in order to exist.

As you move up and to the right of the periodic table, the electronegative properties increase. To form a hydrogen bond, elements would have to be shared with hydrogen. Each element becomes increasingly electronegative as you move further right on the periodic table, with the exception of noble gases (which aren't particularly reactive).

In order to obtain stability, atoms C, H, O, and N would therefore most likely desire to share their electrons (i.e., they are more electronegative because they wish to "hog" electrons). Due to its intermediate electronegativity, hydrogen has a mid-range potential for forming bonds with other molecules.

Learn more about hydrogen element here:

brainly.com/question/16979348

#SPJ4

8 0
2 years ago
PLZ HURRY
vodomira [7]
What is the question or problem you want to solve?
7 0
3 years ago
Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
Maksim231197 [3]

The theoretical yield of SnS_2 will be 4.20 grams while the percent yield will be 7.93%

<h3>How is yield calculated?</h3>

From the equation of the reaction, the mole ratio of SnBr_4 to Na_2S is 1:2.

Mole of 48.1 mL, 0.478 M  SnBr_4 = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M   Na_2S = 0.160 x 48.8/1000 = 0.0078 moles

SnBr_4Na_2S is the limiting reactant.

Mole ratio of  SnBr_4  and SnS_2 = 1:1

Equivalent mole of  SnS_2 = 0.023 moles

Mass of 0.023 noles SnS_2= 0.023 x 182.81 = 4.20 grams

With 0.0333 g of SnS_2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

More on yields of reactions can be found here: brainly.com/question/17042787

#SPJ1

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

7 0
2 years ago
Why does 13c- have a negative sign
Butoxors [25]
Yes it is just in the back which still makes it negative

5 0
3 years ago
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