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Alexxandr [17]
3 years ago
6

The atomic mass of beryllium (Be) is 9.01 amu. The atomic mass of calcium (Ca), which is in the same group as beryllium, is 40.0

8 amu. Based only on this information, what would you predict to be the atomic mass of magnesium (Mg), which is also in the same group but is between Be and Ca?
Chemistry
2 answers:
bekas [8.4K]3 years ago
8 0
Mg will have a higher amu than Be but a lower amu than Ca.
spin [16.1K]3 years ago
5 0

Answer:

It would have a value between 9.01 amu and 40.08 amu.

Explanation:

Hello,

In this case, considering that magnesium is located between beryllium and calcium, its atomic mass will be between 9.01 amu amdn 40.08 amu based on the nowadays organization of the periodic table based on the atomic sizes as well. In such a way, magnesium's atomic mass is about 24.305 amu. This fact is substantiated via the periodic trends associated with the molar mass which states that the higher the period (the atomic radius as well), the higher the molar mass.

Best regards.

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What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2?
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Answer : The concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2 are, 1.58\times 10^{-4} and 6.3\times 10^{-11} respectively.

Explanation : Given,

pH = 10.2

pH : It is defined as the negative logarithm of the hydrogen ion concentration.

First we have to calculate the hydrogen ion concentration (H^+)

pH=-\log [H^+]

Now put the value of pH in this formula, we get the hydrogen ion concentration.

10.2=-\log [H^+]

[H^+]=6.3\times 10^{-11}

Now we have to calculate the pOH of the solution.

pH+pOH=14

Now put the value of pH, we get the value of pOH.

10.2+pOH=14

pOH=14-10.2

pOH=3.8

Now we have to calculate the hydroxide ion concentration (OH^-)

pOH=-\log [OH^-]

Now put the value of pOH in this formula, we get the hydroxide ion concentration.

3.8=-\log [OH^-]

[OH^-]=1.58\times 10^{-4}

Therefore, the concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2 are, 1.58\times 10^{-4} and 6.3\times 10^{-11} respectively.

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3 years ago
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Which claim about the universality of gravity is not supported by evidence?
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Answer:

b because  i said so

Explanation:

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Ammonia gas (NH3) combines with oxygen gas (O2) to form diatomic nitrogen gas and water vapor. If 4.0 grams of ammonia react, ho
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Answer:

1.13 L

Explanation:

First, we have to write the chemical equation for the reaction between ammonia gas (NH₃) and oxygen gas (O₂) to give nitrogen gas (N₂) and water (H₂O), as follows:

NH₃(g) + O₂(g) → N₂(g) + H₂O(g)

Then, we have to balance the equation (we write first the coefficient 2 for NH₃ to balance N atoms, then a coefficient of 3 for H₂O to balance H atoms, and finally 1/3 to balance the O atoms):

2 NH₃(g) + 3/2 O₂(g) → N₂(g) + 3 H₂O(g)

In the balanced equation, we can see that 1 mol of N₂ is produced from 2 moles of NH₃. We convert the moles of NH₃ to grams by using its molecular weight (MW):

MW(NH₃) = 14 g/mol N x 1 + (1 g/mol H x 3) = 17 g/mol

grams of NH₃ = 17 g/mol x 2 = 34 g

Thus, we have the stoichiometric ratio:

1 mol of N₂/2 mol NH₃ = 1 mol of N₂/34 g NH₃

To calculate how many moles of N₂ are produced from 4.0 of NH₃, we multiply the mass by the conversion factor:

4.0 g NH₃ x 1 mol of N₂/34 g NH₃ = 0.1176 moles N₂

Finally, we calculate the liters of N₂ gas by using the ideal gas equation:

PV = nRT ⇒ V = nRT/P

We introduce the data in the equation:

T = 32.00°C + 273 = 305 K

P = 2.6 atm

R = 0.082 L.atm/K.mol (is the gas constant)

n= 0.1176 moles

⇒ V = nRT/P = (0.1176 mol x 0.082 L.atm/K.mol x 305 K)/(2.6 atm)

                     = 1.13 L

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