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Sav [38]
3 years ago
7

Compound has a molar mass of and the following composition: element mass % carbon 58.77% hydrogen 13.81% nitrogen 27.42% Write t

he molecular formula of .
Chemistry
1 answer:
lora16 [44]3 years ago
8 0

Answer: C5H14N2

Explanation:

The element mass are:

C = 58.77 g

H = 13.81 g

N = 27.42 g

To get their moles, we have to divide by the molar mass which will be:

C: 58.77 / 12.01 = 4.8934

H: 13.81 / 1.008 = 13.7004

N: 27.42 / 14.01 = 1.9572

We then divide by the smallest mole which will be:

C: 4.8934 / 1.9572 = 2.5

H: 13.7004 / 1.9572 = 7

N: 1.9572 / 1.9572 = 1

We then multiply by 2 so that we can get whole number ratio:

C: 2.5 × 2 = 5

H: 7 × 2 = 14

N: 1 × 2 = 2

Therefore, the empirical formula will be = C5H14N2

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You have a mass of 54 kg and are sitting on a stool. The normal force the stool applies on you is ...
Karo-lina-s [1.5K]

Answer:

529.2 N

Explanation:

As we have studied the first law of motion, which states that every action has some reaction, equal in magnitude but having an opposite direction.

The force that is acting on the student will be due to gravitational force, that is equal to his weight.

                                              F=mg: 54kg x 9.8m/s^2 =529.2 N

So the weight of student is exerting downwards towards the stool and land. The stool will also exert a force on the student that will be equal in magnitude but opposite in direction, then it will be 529.2 N.

This is because the student is sitting in a constant state and all the weight is exerted on the stool.

Note: This answer is very generic supposing that all the weight of the student is on stool. But, if we suppose that student's legs are on floor so it means the force of gravity acting on the stool has become less because student's mass on stool is less. So the answer would be a force somehow less than 529.2 N.  However, since the question asked normal force, it would be weight of student in general terms.

Hope it helps!

7 0
3 years ago
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Elis [28]

Answer:

It is true

Explanation:

6 0
3 years ago
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. The compound Fe(NO3)3(s) is classified as a(n):?. a. polyatomic compound. b. molecular compound. c. ionic compound. d. multi-a
patriot [66]
<span>the best answer is C i.e is ionoic compound. but all other option sare quite close enough but option  B is sure wrong. because A molecular compound does not separate in a solvent.</span>
5 0
3 years ago
N2H4 + N2O4 --&gt; N2 + H2O
ahrayia [7]

Answer:

  1. The limiting reagent is N2O4
  2. 14,09g

Explanation:

  • First, we adjust the reaction.

2N_{2} H_{4} + N_{2} O_{4} ⇄6N_{2} +  4H_{2}O

  • Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using N_{2} H_{4} to form H_{2}O

               molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4}  }{32,04\frac{g}{mol}  N_{2} H_{4} }

                                           molH_{2} O = 1, 125 mol

Using N_{2} O_{4} to form H_{2} O

              molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4}  }{92\frac{g}{mol}  N_{2} O_{4} }

                                           molH_{2} O = 0,783 mol

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴                          MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}

                                      MassOfH_{2}O = 14,09g

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Lao tzu believed that _____.
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