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2 years ago

In a voltaic (galvanic) cell, oxidation occurs at the _ and is where _ in the salt bridge moves toward.

1 answer:

4 0

In a voltaic (galvanic) cell, oxidation occurs at the anode and is where anions in the salt bridge moves toward.

<h3>What is Galvanic Cell ?</h3>

Galvanic Cell or Voltaic Cell is an electrochemical cell that converts the energy of spontaneous redox reactions into electrical energy. In galvanic cell oxidation occurs at the anode and reduction occurs at the cathode. The anode is positive and cathode is negative, anode attracts anions from solution in an electrolytic cell.

Thus from the above conclusion we can say that In a voltaic (galvanic) cell, oxidation occurs at the anode and is where anions in the salt bridge moves toward.

Learn more about the Galvanic Cell here: brainly.com/question/15096829

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1.) The process for converting ammonia to nitric acid involves the conversion of NH3 to

Firdavs [7]

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a) 1.39 g ; b) O₂ is limiting reactant, NH₃ is excess reactant; c) 0.7 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

MM: 17.03 32.00 30.01

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

Mass/g: 1.5 1.85

2. Calculate the moles of each reactant

$\text{moles of NH}_{3} = \text{1.5 g NH}_{3} \times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}} = \text{0.0881 mol NH}_{3}\\\\\text{moles of O}_{2} = \text{1.85 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.057 81 mol O}_{2}$

3. Calculate the moles of NO we can obtain from each reactant

From NH₃:

The molar ratio is 4 mol NO:4 mol NH₃

$\text{Moles of NO} = \text{0.0881 mol NH}_{3} \times \dfrac{\text{4 mol NO}}{\text{4 mol NH}_{3}} = \text{0.0881 mol NO}$

From O₂:

The molar ratio is 4 mol NO:5 mol O₂

$\text{Moles of NO} = \text{0.057 81 mol O}_{2}\times \dfrac{\text{4 mol NO}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NO}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO.

The excess reactant is NH₃.

5. Calculate the mass of NO formed

$\text{Mass of NO} = \text{0.046 25 mol NO}\times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \textbf{1.39 g NO}$

6. Calculate the moles of NH₃ reacted

The molar ratio is 4 mol NH₃:5 mol O₂

$\text{Moles reacted} = \text{0.057 81 mol O}_{2} \times \dfrac{\text{4 mol NH}_{3}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NH}_{3}$

7. Calculate the mass of NH₃ reacted

$\text{Mass reacted} = \text{0.046 25 mol NH}_{3} \times \dfrac{\text{17.03 g NH}_{3}}{\text{1 mol NH}_{3}} = \text{0.7876 g NH}_{3}$

8. Calculate the mass of NH₃ remaining

Mass remaining = original mass – mass reacted = (1.5 - 0.7876) g = 0.7 g NH₃

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3 years ago

Which of the compounds below is not an example of a molecular solid?

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E
Water is the only polar compound so I guess that must be odd one out. I’m sorry I’m of no actual help.

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4 years ago

In a voltaic (galvanic) cell, oxidation occurs at the _____ and is where _____ in the salt bridge moves toward.

In a voltaic (galvanic) cell, oxidation occurs at the _ and is where _ in the salt bridge moves toward.