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Stels [109]
1 year ago
10

In a voltaic (galvanic) cell, oxidation occurs at the _____ and is where _____ in the salt bridge moves toward.

Chemistry
1 answer:
Anna11 [10]1 year ago
4 0

In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

<h3>What is Galvanic Cell ?</h3>

Galvanic Cell or Voltaic Cell is an electrochemical cell that converts the energy of spontaneous redox reactions into electrical energy. In galvanic cell oxidation occurs at the anode and reduction occurs at the cathode. The anode is positive and cathode is negative, anode attracts anions from solution in an electrolytic cell.

Thus from the above conclusion we can say that In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

Learn more about the Galvanic Cell here: brainly.com/question/15096829

#SPJ1

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Answer:

d. Temperature and number of molecules of gas  

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the <em>variables</em>.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are <em>wrong</em>, because pressure is a variable.

b is <em>wrong</em>, because volume is a variable.

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3 years ago
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Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

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vredina [299]

Answer:

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1-propanol is a polar molecule, therefore, it will dissolve in water.

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