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Stels [109]
2 years ago
10

In a voltaic (galvanic) cell, oxidation occurs at the _____ and is where _____ in the salt bridge moves toward.

Chemistry
1 answer:
Anna11 [10]2 years ago
4 0

In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

<h3>What is Galvanic Cell ?</h3>

Galvanic Cell or Voltaic Cell is an electrochemical cell that converts the energy of spontaneous redox reactions into electrical energy. In galvanic cell oxidation occurs at the anode and reduction occurs at the cathode. The anode is positive and cathode is negative, anode attracts anions from solution in an electrolytic cell.

Thus from the above conclusion we can say that In a voltaic (galvanic) cell, oxidation occurs at the <u>anode</u> and is where <u>anions</u> in the salt bridge moves toward.

Learn more about the Galvanic Cell here: brainly.com/question/15096829

#SPJ1

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What is the frequency of light with a wave- length of 4.0 ×10−7 m?
Kisachek [45]

7.5x10^14 Hz. I just worked it out on paper.

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The N H 2 group makes the molecule an amine. Like alcohols, amines can participate in hydrogen bonding. If the drawn molecule en
lesantik [10]

Answer:

a hydrogen bond between the hydrogen of water and the nitrogen of the amine

a hydrogen bond between the oxygen of water and a hydrogen from the -NH2 group

Explanation:

A hydrogen bond is formed between molecules in which hydrogen is bonded to a highly electronegative element.

In amines, hydrogen is bonded to nitrogen while in water, hydrogen is bonded to oxygen. Both are highly electronegative elements hence hydrogen bonding is possible between amines and water.

This hydrogen bond may involve;

The hydrogen of water and the nitrogen of the amine

Or

The oxygen of water and a hydrogen from the -NH2 group

7 0
3 years ago
Describe what happens when a liquid is heated to its boiling point
kolezko [41]
Boiling<span> is the process by which a </span>liquid<span> turns into a vapor when it is </span>heated to its boiling point<span>. The change from a </span>liquid<span> phase to a gaseous phase occurs when the vapor pressure of the </span>liquid<span> is equal to the atmospheric pressure exerted on the</span><span>liquid</span>
7 0
3 years ago
Determine the pH of the resulting solution if 25 mL of 0.400 M strychnine (C21H22N2O2) is added to 50 mL of 0.200 M HCl? Assume
DIA [1.3K]

Answer:

pH = 4.56

Explanation:

The strychnine reacts with HCl as follows:

C₂₁H₂₂N₂O₂ + HCl ⇄ C₂₁H₂₂N₂O₂H⁺ + Cl⁻

<em />

For strychnine buffer:

pOH = 5.74 + log [C₂₁H₂₂N₂O₂H⁺] / [C₂₁H₂₂N₂O₂]

Initial moles of C₂₁H₂₂N₂O₂ are:

0.025L * (0.400 mol / L) = 0.01 moles C₂₁H₂₂N₂O₂

And of HCl are:

0.05L * (0.200 mol / L) = 0.01 moles HCl

That means after the reaction, you will have just 0.01 moles of C₂₁H₂₂N₂O₂H⁺ in 50mL + 25mL = 0.075L. And molarity is:

[C₂₁H₂₂N₂O₂H⁺] = 0.01 mol / 0.075L = 0.1333M

This conjugate acid, is in equilibrium with water as follows:

C₂₁H₂₂N₂O₂H⁺(aq) + H₂O(l) ⇄ C₂₁H₂₂N₂O₂ + H₃O⁺

<em />

<em>Where Ka = Kw / Kb = 1x10⁻¹⁴ / 1.8x10⁻⁶ = 5.556x10⁻⁹</em>

<em />

Ka is defined as:

Ka = 5.556x10⁻⁹ = [C₂₁H₂₂N₂O₂] [H₃O⁺] / [C₂₁H₂₂N₂O₂H⁺]

In equilibrium, concentrations are:

C₂₁H₂₂N₂O₂ = X

H₃O⁺ = X

C₂₁H₂₂N₂O₂H⁺ = 0.1333M - X

Replacing in Ka expression:

5.556x10⁻⁹ = [X] [X] / [0.1333M - X]

7.39x10⁻¹⁰ - 5.556x10⁻⁹X = X²

7.39x10⁻¹⁰ - 5.556x10⁻⁹X - X² = 0

Solving for X:

X = - 2.72x10⁻⁵M → False solution. There is no negative concentrations

X = 2.72x10⁻⁵M → Right solution.

As H₃O⁺ = X

H₃O⁺ = 2.72x10⁻⁵M

And pH = -log H₃O⁺

<h3>pH = 4.56</h3>
4 0
3 years ago
. Write the following isotope in nuclide notation (e.g., “ ”): copper-70
vekshin1

Answer:

{\boxed{\text{$_{29}^{70}${Cu}}}

Explanation:

The atomic number (Z) of copper is 29 and this isotope has an atomic mass (A) of 70.

The general symbol for an isotope E is _{Z}^{A}\text{E}.

The atomic number is a left subscript, and the atomic mass is a left superscript.

\rm {\text{The nuclide notation for copper-70 is }}{\boxed{\textbf{$_{29}^{70}${Cu}}}

4 0
3 years ago
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