Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
IDK
Step-by-step explanation:
<em>X = 2 cm</em>
Volume = Bh= 8×5×1/2×X= 80
X = 80/20 = 4
If you are being asked to simplify, just combine like terms; such as, all the g’s and all the numbers so, your answer should look something like: 7g+6
Answer:
19. D
20. A
Step-by-step explanation:
19. Tan= opp/adj
20. Sin= opp/hyp
