To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
Volume is a three-dimensional scalar quantity. The volume of the right-triangular pyramid is 1.008 m³.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of a right-triangle pyramid is one-third of the product of its base area and its height. Therefore, the volume is,
Volume = (1/3) × 0.5 × 1.4 × 1.8 × 2.4
= 1.008 m³
Hence, the volume of the right-triangular pyramid is 1.008 m³.
Learn more about Volume:
brainly.com/question/13338592
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Answer:
6 numbers greater than 6, plus 1,3 and 5- so nine total.
9/12, simplified 3/4
