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Lady_Fox [76]
3 years ago
7

Abhasra bought 8 writing utensils for a

Mathematics
1 answer:
padilas [110]3 years ago
5 0

Answer:

6 pens for 36$ then 2 pencils for 2$ equal 38$

Step-by-step explanation:

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The sides of the figure below measure 12, 17, and 20 centimeters. Find the
vlada-n [284]

Answer:

The perimeter should be 49 centimeters

Step-by-step explanation:

You're just adding up the centimeters that are stated in the question and then just putting the number there in the answer

8 0
3 years ago
For which values of c does the following polynomial have two complex roots? X^2+4x+C
Grace [21]

For this case we have that by definition, the discriminant of a quadratic expression is given by:

d = b ^ 2-4 (a) (c)

If the discriminant is less than zero then the expression has two different complex roots.

In this case we have the following expression:

x ^ 2 + 4x + c

So we have to:

a = 1\\b = 4\\c = c\\

The discriminant is given by:

d = 4 ^ 2-4 (1) (c)\\d = 16-4c

Then, if we want two complex roots it must be fulfilled that:

16-4c

Thus, the expression has two complex roots for all values greater than 4.

ANswer:

c> 4

5 0
3 years ago
Find sin of i need help can u help me
astraxan [27]

Answer:

The answer is

Step-by-step explanation:

6 0
3 years ago
A pooled variance is an estimated weighted variance made up of several different populations when the mean of each population ma
Marta_Voda [28]

Answer:

True

Step-by-step explanation:

Considering the above definition of Pooled Variance, the correct answer is TRUE.

This is because Pooled variance is used to determine the reasonable estimates of variance, where several repeated tests are expected at each value.

This helps to provide greater precision estimates of variance.

4 0
3 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
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