<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
Answer:

Step-by-step explanation:
By definition if two events are mutually exclusive then they are disjoint events, that is, they can not occur at the same time.
In general terms we say that events are mutually exclusive, then:

In this case we have that

But A and B are mutually exclusive events, then 
Answer:
False!
Step-by-step explanation:
As C is not equal to -13 (number line)
So, your answer would be false.
hope it helps!
32=16x2=2x2x2x2x2=2^5
48=24*2=6x4x2=2x3x2x2x2
Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:
2^4=2x2x2x2=16
The Greatest Common Factor (GCF) of 32 and 48 is 16.
Answer:
Step-by-step explanation:
- Let the speed of the boat be x
- Speed against the current in the river is x - 2
<u>Time in the river:</u>
<u>Time in the lake:</u>
<u>The difference:</u>
Solve for x to find the speed of the boat
<u>Multiply both sides by x(x - 2) to clear the fraction:</u>
- 6x = 15(x - 2) - x(x - 2)
- 6x = 15x - 30 - x² + 2x
- x² - 11x + 30 = 0
- (x - 5)(x - 6) =0
- x -5 = 0, x - 6 = 0
- x = 5 km/h, x = 6 km/h