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ArbitrLikvidat [17]
3 years ago
15

Given P(A) = 0.4 and P(B) = 0.6, do the following.(a) If A and B are independent events, compute P(A and B).(b) If P(A | B) = 0.

5, compute P(A and B).
Mathematics
2 answers:
ycow [4]3 years ago
5 0

Answer:

Solution in photo

Step-by-step explanation:

Hoochie [10]3 years ago
3 0

Answer:

a) 0.24

b) 0.3

Step-by-step explanation:

Given the following probability

P(A) = 0.4 P(B) = 0.6

a) P(A and B) =P(A)P(B) {Independent)

P(A and B) = 0.4×0.6

P(A and B) = 0.24

b) Given P(A | B) = 0.5, this is a conditional probability

If P(A | B) = P(A and B)/P(B)

Since If P(A | B) = 0.5

0.5 = P(A and B)/P(B)

P(A and B) = 0.5(P(B)

P(A and B) = 0.5(0.6)

P(A and B) = 0.3

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trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0
3 years ago
Read 2 more answers
If A and B are mutually exclusive events with P(A)= 0.3 and P(B)= 0.5, then P(A and B)=
arsen [322]

Answer:

P (A\ and\ B) = 0

Step-by-step explanation:

By definition if two events are mutually exclusive then they are disjoint events, that is, they can not occur at the same time.

In general terms we say that events are mutually exclusive, then:

P (A\ and\ B) = 0

In this case we have that

P(A)= 0.3\\\\P(B)= 0.5

But A and B are mutually exclusive events, then P (A\ and\ B) = 0

4 0
3 years ago
1 BAJILLION POINTS!!
Natalija [7]

Answer:

False!

Step-by-step explanation:

As C is not equal to -13 (number line)

So, your answer would be false.

hope it helps!

4 0
3 years ago
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What is the greatest common factor of 32a and 48b
SpyIntel [72]

32=16x2=2x2x2x2x2=2^5

48=24*2=6x4x2=2x3x2x2x2

Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:

2^4=2x2x2x2=16

The Greatest Common Factor (GCF) of 32 and 48 is 16.

5 0
2 years ago
a wildlife photographer photographs a crocodile and then paddles against a river current for 6 km. Then, hoping to photograph a
rusak2 [61]

Answer:

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Step-by-step explanation:

  • Let the speed of the boat be x
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<u>Time in the river:</u>

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<u>Time in the lake:</u>

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<u>The difference:</u>

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Solve for x to find the speed of the boat

<u>Multiply both sides by x(x - 2) to clear the fraction:</u>

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3 years ago
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