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ArbitrLikvidat [17]
3 years ago
15

Given P(A) = 0.4 and P(B) = 0.6, do the following.(a) If A and B are independent events, compute P(A and B).(b) If P(A | B) = 0.

5, compute P(A and B).
Mathematics
2 answers:
ycow [4]3 years ago
5 0

Answer:

Solution in photo

Step-by-step explanation:

Hoochie [10]3 years ago
3 0

Answer:

a) 0.24

b) 0.3

Step-by-step explanation:

Given the following probability

P(A) = 0.4 P(B) = 0.6

a) P(A and B) =P(A)P(B) {Independent)

P(A and B) = 0.4×0.6

P(A and B) = 0.24

b) Given P(A | B) = 0.5, this is a conditional probability

If P(A | B) = P(A and B)/P(B)

Since If P(A | B) = 0.5

0.5 = P(A and B)/P(B)

P(A and B) = 0.5(P(B)

P(A and B) = 0.5(0.6)

P(A and B) = 0.3

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So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
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r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
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Step-by-step explanation:

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Step-by-step explanation:

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