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Lana71 [14]
2 years ago
13

What two values would complete the table so it represents a proportional relationship?

Mathematics
1 answer:
larisa86 [58]2 years ago
8 0
So if its proportional, y/x should be constant:
1/0.2=5
5/1=5
20/4=5
so, x=4 and y=5
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The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution. What amount of each solution do
xenn [34]

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

\texttt{ }

<em>Let:</em>

<em>Volumes of 2% Solution = x</em>

<em>Volumes of 10% Solution = y</em>

\texttt{ }

<em>Total Volume = 10 ml</em>

\boxed{x + y = 10} → <em>Equation 1</em>

\texttt{ }

<em>The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution</em>.

2 \% x + 10 \% y = 6 \% (10)

2x + 10y = 6(10)

\boxed{x + 5y = 30} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1 - Equation 2:</em>

( x + y ) - ( x + 5y ) = 10 - 30

-4y = -20

y = -20 \div -4

y = 5 \texttt{ ml}

\texttt{ }

x + y = 10

x + 5 = 10

x = 5 \texttt{ ml}

\texttt{ }

<h2>Conclusion:</h2>

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

6 0
2 years ago
The best way to achieve significant increases in interest after all in a savings account is through?
Alekssandra [29.7K]

Answer: The answer is (d) Compounding.

Step-by-step explanation:  We are given four options out of we are to select the best way through which we can achieve significant increases in interest after all in a savings account.

Increases in principle and increases in time will not give the result, because we are talking about a fixed amount of money for a fixed time.

Also, increases in interest is not in our hand.

So, only we can do is compounding. Here, in same amount of money and time, the rate of interest will automatically increase.

Thus, the correct option is (d) Compounding.

4 0
2 years ago
1+1 equals what i don't know big prize i give all my brainy points i just graduated don't need this anymore
Marina86 [1]

\huge \mathbb \pink{HELLO }

\sf \green{1  + 1 \: is \: 2}

\huge \mathcal \orange{HAVE \: A \: GOOD \: DAY }

6 0
1 year ago
Hello, I dont understande this, can someone please explain what it is.
n200080 [17]

The required diameter of dwarf planet is 10^{6}  m.

<h3>What is a statement?</h3>

A statement is a declarative sentence that is either true or false but not both. A statement is sometimes called a proposition. The key is that there must be no ambiguity. To be a statement, a sentence must be true or false, and it cannot be both.

Given:

The given statement is the diameter of 3 planet is

planet A= 10^{9} m= 1000000000m

planet B=10^{7} m=10000000m

planet C= 10^{8} m=100000000m

According to given question we have

A dwarf planet is discovered with a radius is 1/100 times of radius of planet C.

Radius of planet C =100000000/2=  50000000m

Radius of  dwarf planet = 1/100 times of radius of planet C.

Radius of  dwarf planet = 1/100 * 50000000m

Radius of  dwarf planet = 500000 m=5*10^{5} m

Diameter of dwarf planet =2*500000 m=1000000 m=10^{6}  m

Therefore, the required diameter of dwarf planet is 10^{6}  m.

Learn more details about statement here:

brainly.com/question/2285414

#SPJ1

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1 year ago
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No I haven’t but y could search it up
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3 years ago
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