All categories

3 years ago

Explain the steps for dividing decimals. Write three or four sentences.

Mathematics

2 answers:

ryzh [129]3 years ago

8 0

Answer:

1.First Move the decimal point in the divisor and dividend.

2.Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.

3.Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.

Step-by-step explanation:

I got it from google tbh

crimeas [40]3 years ago

8 0

I think it the 2 one

You might be interested in

Evaluate the function f(x)=3x-7if x=6

notka56 [123]

Answer:

if x=6, then f(6)=11

8 0

3 years ago

Read 2 more answers

Help i have math homework and im real bad at it i got a B- last year so help

Natalka [10]

4y-12 is the answer

7 0

2 years ago

Read 2 more answers

malia has $500 to purchase water bottles and pairs of socks for a fundraiser for her school's cross country team. She needs to b

BigorU [14]

Answer

6.9step-by-step explanation: simple math really6 1/2 times 0.6 = 3.9but if you are just doing 6

Step-by-step explanation:

4 0

2 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago

F(x) = x4/5(x − 6)2 find the critical numbers of the function

Fiesta28 [93]

You can find the critical numbers by finding the derivative of the function and solving for 0.

F(x) = x(4/5)(x-6)(2) = x(8/5)(x-6) = (8/5)(x^2 - 6x)

Taking the derivative:
F'(x) = (8/5)(2x - 6)
F'(x) = 0 at x = 3,

critical number = 3

5 0

3 years ago