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gtnhenbr [62]
3 years ago
8

PLEASE HELP

Mathematics
2 answers:
vova2212 [387]3 years ago
6 0

A, B, and D      I hope this helps :)

Lyrx [107]3 years ago
4 0
A B And D are correct ones
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Which of the following options have the same value as 62%, percent of 45?
brilliants [131]

Answer:

A and C

Step-by-step explanation:

A is correct because converting the percentage to decimal form will give you the value of that percentage, and 62% will be the same as 0.62 in decimal form.

C is the same in a less simplified form because 62/100 = 0.62, so it is the same as A when you convert it to decimal form, 0.62 · 45.

8 0
3 years ago
Find the dimensions of a rectangle divided into two equal rectangles of maximum area that has total perimeter (including the mid
lilavasa [31]

The dimensions for this rectangle are b= 30 ft and h=20 ft.

<h3>Perimeter</h3>

The perimeter of a geometric figure is the sum of its sides.

The question  gives:

  • the geometric figure - rectangle
  • the total perimeter - 120 ft

Therefore for the perimeter, you have

P= \frac{b}{2} +\frac{b}{2}+ h+ h +h

P=2b+3h

2b+3h=120 (1)

From equation 1, you can write:

2b=120-3h

b=\frac{120-3h}{2}

b= 60 - \frac{3h}{2} (2)

The area for the rectangle is given by A= bh. Therefore, by replacing (2) in the formula for rectangle area, you have:

A= (60-\frac{3h}{2} )* h\\ \\ A= 60h-\frac{3h^2}{2}

The maximum area will be calculated from the derivation of the previous equation of area.

\frac{dA}{dh}=60-2*\frac{3h}{2}\\ \\  \frac{dA}{dh}=60-3h

The maximum area can be found when the first derivative is equal to zero. Thus,

60-3h=0

-3h=-60 *(-1)

3h=60

h=20

Now, you know the height and from equation 2 (b= 60 - \frac{3h}{2} ) you can find the base.

b= 60 -\frac{3*20}{2}

b=60 - 3*10

b=60-30

b=30

Read more about the First Derivative Test here:

brainly.com/question/6097697

#SPJ1

8 0
2 years ago
PLEASE HELP BRAINLIEST TO WHOEVER ANSWERS RIGHT
tensa zangetsu [6.8K]
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values.  The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values.  The middle (of the lower half) is Q1, which is on the 9th line (80,78)

The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
6 0
3 years ago
PLEASE PLEASE PLEASE HELP! Please explain step by step!! Please please I'll give enough points!
ArbitrLikvidat [17]
1)
The distance between points A and B is;
d= \sqrt{(x2-x1)^{2} + (y2-y1)^{2} } \\&#10;d= \sqrt{(1-5)^{2} +(12+8)^{2}}\\ &#10;d= \sqrt{(-4)^{2} + (20)^{2}}\\&#10;d=\sqrt{16+400}\\&#10;d=\sqrt{416}\\&#10;d=4\sqrt{26}, 
and if you wanted to you could measure out the legs of that hypotenuse using the slope between A and B, but I'm going to show you the easier way;
Δx = 4
Δy = -20
So from the midpoint, add 4 to the x-value and subract 20 from the y-value.
{(5+4),(-8-20)}
(9,-28) is the endpoint.

2)
Do the same thing as I did above;
d= \sqrt{(x2-x1)^{2} + (y2-y1)^{2} } \\ &#10;d= \sqrt{(5-(-3))^{2} +(5-(-4))^{2}}\\&#10;d=\sqrt{(5+8)^{2}+(5+4)^{2}}\\&#10;d=\sqrt{(13)^{2}+(9)^{2}}\\&#10;d=\sqrt{169+81}\\&#10;d=\sqrt{250}\\&#10;d=5\sqrt{10}
So 5\sqrt{10} is the distance.

Sorry for the delay, life delayed me a ton ,:D
4 0
4 years ago
Rotate the point (5,5) around the origin 180 degrees counterclockwise. State the image
Degger [83]

Answer: (-5,-5) --> (-x,-y)

Step-by-step explanation:

90 degree rotation: (-y,x)

180 degree rotation: (-x,-y)

270 degree rotation: (y,-x)  

3 0
3 years ago
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