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3 years ago

What is the conversion for 2.0 m + 3.33 m + 4 m =

Chemistry

1 answer:

4vir4ik [10]3 years ago

7 0

Answer:

933/100

9.33m

....... . . . . .. .. .

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Explain, in terms of electron configuration why atoms of the radioisotope produced by the sixth decay in the U-238 disintegratio

Troyanec [42]

Answer:

The reason they don't react is because Elements with full octets are stable, the Elements with no unpaired electrons do not react at all in the decay.

4 0

3 years ago

Process of transformation of CH3CH2CH2CH2CL to CH3CH(OH)CH(OH) CH3

egoroff_w [7]

Answer:

Prefixes for carbon chain length are

1 carbon = meth

2 carbon = eth

3 = prop

4 = but

5 = pent

6 = hex

7 = hept

8 = oct

9 = non

10 = dec

Explanation:

4 0

3 years ago

The density of a 45.0 mass % solution of ethanol (C2H5OH) in water is 0.873 g/mL. What is the molarity of the solution?

antoniya [11.8K]

Answer : The concentration of solution is, 8.53 M.

Explanation :

As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}$

$\text{Volume of solution}=\frac{100g}{0.873g/mL}=114.5mL$

Now we have to calculate the molarity of solution.

Mass of $C_2H_5OH$ = 45.0 g

Volume of solution = 114.5 mL

Molar mass of $C_2H_5OH$ = 46.07 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{45.0g\times 1000}{46.07g/mole\times 114.5mL}=8.53mole/L=8.53M$

Therefore, the concentration of solution is, 8.53 M.

6 0

3 years ago

Help me answer this chemistry question. thank you!

tatiyna

Answer:

78.85

Explanation:

To <u>calculate the average atomic mass of the isotopes </u>we use the <em>given masses and abundances</em>, as follows:

Mass of Isotope 1 * Abundance of Isotope 1 + Mass of Isotope 2 * Abundance of Isotope 2 + ....

In other words:

78 amu * 75/100 + 81 amu * 15/100 + 82 amu * 10/100 = 78.85

So the answer is 78.85.

8 0

3 years ago

Anybody Understand this question please help me !

zlopas [31]

Answer:

$m_{Sn}=630.57gSn$

Explanation:

Hello!

In this case, according to the chemical reaction:

$SnO_2+2H_2\rightarrow Sn+2H_2O$

We can evidence the 2:1 mole ratio between hydrogen and tin, thus, we perform the following stoichiometric setup to obtain the mass of produced tin:

$m_{Sn}=21.46gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molSn}{2molH_2} *\frac{118.71gSn}{1molSn} \\\\m_{Sn}=630.57gSn$

Best regards!

7 0

3 years ago