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fredd [130]
3 years ago
9

Which of the following SI or metric units is a base unit?

Chemistry
1 answer:
Olin [163]3 years ago
8 0
3. Ampere is the base unit for electric current.
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How many moles are in 68.5 liters of oxygen gas at STP?
g100num [7]
We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.

68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2
7 0
3 years ago
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A 455 g piece of bopper tubing is heated to 89.5 C and placed in an insulated vessel containing 159 g of water at 22.8 C. Assumi
postnew [5]

Answer:

The final temperature of the setup = 36.6°C

Explanation:

Let the final temperature of the setup be T

Heat lost by the copper tubing = Heat gained by water and the vessel

Heat lost by the copper tubing = mC ΔT = 455 × 0.387 × (89.5 - T) = (15759.61 - 176.1T) J

Heat gained by water = mC ΔT = 159 × 4.186 × (T - 22.8) = (665.6T - 15175.1) J

Heat gained by vessel = c ΔT = 10 × (T - 22.8) = (10T - 228) J

Heat lost by the copper tubing = Heat gained by water and the vessel

(15759.61 - 176.1T) = (665.6T - 15175.1) + (10T - 228)

851.7 T = 31162.71

T = 36.6°C

7 0
3 years ago
A physical property of halite (table salt) is its _____.
Katarina [22]
Boiling point, melting point, Appearance, mass, and taste.<span />
4 0
3 years ago
A quanta of electromagnetic energy is called *
Murrr4er [49]

Answer:

X-ray photon is a quantum of electromagnetic energy.

8 0
3 years ago
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How much concentrated solution would it take to prepare 2.90 L of 0.420 M HCl upon dilution with water
Zanzabum

Answer:

the quantity required can go from 117 ml (for maximum concentration) up to 2900 ml ( if the concentrated solution has molarity =0.420 M)

Explanation:

the amount of water required to dilute a solution V₁ liters of Molarity M₁ to V₂ liters of M₂

moles of hydrochloric acid =  M₁ * V₁= M₂ * V₂

V₁ =   V₂ * M₂/M₁

where

M₂ = 0.420 M

V₂ =2.90 L

Since the hydrochloric acid can be concentrated up to 38% p/V  ( higher concentrations are possible but the evaporation rate is so high that handling and storage require extra precautions, like cooling and pressurisation)

maximum M₁ =38% p/V = 38 gr/ 0.1 L / 36.5 gr/mol = 10.41 M

then

min V₁ =   V₂ * M₂/ max M₁ =  2.90 L* 0.420 M/ 10.41 M= 0.117 L = 117 ml

then the quantity required can go from 117 ml up to 2900 ml ( if M₁ = M₂)

5 0
3 years ago
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