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2 years ago

Are any of these equations redox reactions? if so what are their reducing and oxidizing agents?

1 answer:

8 0

Yes, Fe(s)+CuSO4→FeSO4(aq)+Cu(s) is a redox reaction. The reducing agent is Fe(s), while the oxidizing agent is CuSO4.

<h3>Oxidation-reduction reaction (redox)</h3>

Oxidation-reduction reaction is the type of reaction in which electrons are transferred from one element to another. A compound or an element either gains are looses an electron in redox reactions.

Fe(s)+CuSO4→FeSO4(aq)+Cu(s)

From the equation above, Fe(s) is the reducing agent because it gives away 2 electrons and undergoes oxidation reaction.

From the equation above, CuSO4 is an oxidizing agent because it gives oxygen to Fe(s) and undergoes a reduction reaction.

Therefore, the reducing agent is Fe(s), while the oxidizing agent is CuSO4.

Learn more about redox reactions here:

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How many atoms of S are there?

jonny [76]

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3 years ago

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3 years ago

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Answer:

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2 years ago

Balance the following redox equation using the smallest integers possible and select the correct coefficient for the hydrogen su

goldfiish [28.3K]

Answer:

Coefficient of $HSO_{3}^{-}$ is 5

Explanation:

Oxidation: $MnO_{4}^{-}(aq)\rightarrow Mn^{2+}(aq)$

Balance O and H in acidic medium: $MnO_{4}^{-}(aq)+8H^{+}(aq)\rightarrow Mn^{2+}(aq)+4H_{2}O(l)$
Balance charge : $MnO_{4}^{-}(aq)+8H^{+}(aq)+5e^{-}\rightarrow Mn^{2+}(aq)+4H_{2}O(l)$ .............(1)

Reduction: $HSO_{3}^{-}\rightarrow SO_{4}^{2-}$

Balance O and H in acidic medium : $HSO_{3}^{-}(aq)+H_{2}O(l)\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)$
Balance charge : $HSO_{3}^{-}(aq)+H_{2}O(l)-2e^{-}\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)$ ..............(2)

$[2\times eq(1)]+[5\times eq(2)]$ -

Balanced equation: $2MnO_{4}^{-}(aq)+5HSO_{3}^{-}(aq)+H^{+}(aq)\rightarrow 2Mn^{2+}(aq)+5SO_{4}^{2-}(aq)+3H_{2}O(l)$

Coefficient of $HSO_{3}^{-}$ is 5

8 0

3 years ago