Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.
The freezing rain falls and solidifies on a wire fence as the rain is changing from a liquid to a solid state by withdrawing thermal energy, ultimately resulting in freezing.
Answer:
hey you wanna get it right try this one: 48.0 kcal
was released... at constant pressure.
Explanation:
Answer: They are close to each other by 41.03 m^3
Explanation:
From Ideal gas equation, PV = nRT
Where n is negligible
R is gas constant = 8.314 J/mol.k
T = 30 + 273 = 303K
P = 1.02 * 103351.5 = 103351.5 Pascal
Then;
PV = RT
V = P/RT
V = 103351.5/(8.314*303)
V = 41.03m^3
A thick liquid could be one property or its white.....
CaCl2 and KCl are both salts which dissociate in water
when dissolved. Assuming that the dissolution of the two salts are 100 percent,
the half reactions are:
<span>CaCl2 ---> Ca2+ + 2 Cl-</span>
KCl ---> K+ + Cl-
Therefore the total Cl- ion concentration would be coming
from both salts. First, we calculate the Cl- from each salt by using stoichiometric
ratio:
Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles
Cl / 1 mole CaCl2)
Cl- from CaCl2 = 0.1 moles
Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1
mole KCl)
Cl- from KCl = 0.1 moles
Therefore the final concentration of Cl- in the solution
mixture is:
Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)
Cl- = 0.2 moles / 0.5 moles
<span>Cl- = 0.4 moles (ANSWER)</span>
