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Lubov Fominskaja [6]
3 years ago
12

Determine which of the two acute angles has a cosine of 4/5.

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

CosA = 4/5

Step-by-step explanation:

The acute angle with cosine of 4/5

Recall from trigonometry ;

Cosine = Adjacent / hypotenus

From the right angled triangle Given:

For angle A :

Opposite = BC = 8

Hypotenus = AC = 10

Cos A = BC / AC = 8 /10 = 4 /5

CosA = 4/5

For C :

Opposite = AB = 6

Hypotenus = AC = 10

Cos C = 6 /10 = 3 /5

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1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

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2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

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