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Usimov [2.4K]
3 years ago
14

There are four cars entered into a pinewood derby race. in how many different orders can they cross the finish line, assuming th

ere are no ties?
Mathematics
1 answer:
artcher [175]3 years ago
4 0

This is a problem of fundamental counting principle. In a sequence of events, the total possible number of ways all events can performed is the product of the possible number of ways each individual event can be performed. So here there is one car in each place so there 4 possible cars to get the 1st place, 3 possible car for the 2nd place, 2 possible cars for 3rd place and 1 for the 4th place. The 4x3x2x1 = 24 different order 

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grandymaker [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
2x+4y=6<br> 3x=12-6y<br> Solve by elimination
faltersainse [42]

Answer:

no solution

Step-by-step explanation:

2x + 4y = 6......reduces to x + 2y = 3

3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4

so now we have :

x + 2y = 3

x + 2y = 4

ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.

5 0
3 years ago
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Mashcka [7]
The answer is C

So how?

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I hope this helps! :D
6 0
3 years ago
Which statement is true about numbers to the left of 0 on a number line?
NemiM [27]

Answer:

Numbers to the left of 0 on a number line or anywhere are always negative,

Step-by-step explanation:


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