Answer:
E) Please see below as the answer is self -explanatory.
Explanation:
The pareto chart, is used in quality control, and is a combined type of graph, that uses a line-type curve to denote the cumulative percentages of the different types of defects found in a sample (so the maximum value is 100%)
Also, it features a bar chart, which shows the relative occurrence of the different values (as in a histogram) which allows to find easily which defects are more relevant ones, alerting in this way about unacceptable deviations in the manufacturing process (if we are producing a good under given quality standards, for instance).
Answer:
Re-torque the bolts as required while your engine is warm. But if you're using aluminum cylinder heads, you should wait until your engine is complete cooled until re-torquing
Answer:
13177.34 J
Explanation:
Work done = force × distance
work done by the engine = kinetic energy + potential energy + work done friction
kinetic energy due to the car's speed = 1/2mv² = 4468.5 J
potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J
work done by friction = 2870 J
work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J
Explanation:
Okay soo-
Given-
u = 60 km/hr = 60×1000/3600=50/3 m/s
t = 20 s
s = 250 m
a = ?
v = ?
Solution -
Here, acceleration is uniform.
(a) According to 2nd kinematics equation,
s = ut + ½at^2
250 = 50/3 ×20 + 0.5×a×20×20
250-1000/3=200a
(750-1000)/3=200a
a = -250/(3×200)
a = -5/12
a = 0.4167 m/s^2
The required uniform acceleration of the car is 0.4167 m/s^2.
(b) According to 1st kinematics equation
v = u + at
v = 50/3 + (-5/12)×20
v = 50/3-25/3
v = 25/3
v = 8.33 m/s
The speed of the car as it passes the traffic light is 8.33 m/s.
Good luck!
