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3 years ago

Solve the inequality below.Use the drop-down menus to describe the solution and its graph.

Engineering

1 answer:

Sloan [31]3 years ago

3 0

Answer:

make paragraph and solution

Explanation:

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3 years ago

The mass flow rate in a 4.0-m wide, 2.0-m deep channel is 4000 kg/s of water. If the velocity distribution in the channel is lin

IceJOKER [234]

Answer:

V = 0.5 m/s

Explanation:

given data:

width of channel = 4 m

depth of channel = 2 m

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$\frac{\dot{m}}{\rho A} = V$

$V = \frac{4000}{1000*4*2}$

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