Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)
a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1) N + D + Q = 111 coins
b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins
c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:
(1) N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
17 coins N ( x 5 = 85 cents)
22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
and 173 P,
proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78
The correct answer would be -4
explanation:
2x-5<-12, add 5 to both sides so then you get 2x<-8, then divide by two, x<-4.
Answer:
it could be the number in 2015 is 2,330
Step-by-step explanation:
Just add the number of the students in 2014-2016.
1,030+ 1,300=2,330
Plot and connect the points A (2, -2), B (-4, -4), C (-4, -1), D (-2, 3), E (1, 3), F (2, 5), and find the length of BC.
Paul [167]
Answer:
BC = 3 units
Step-by-step explanation:
Given points:
- A = (2, -2)
- B = (-4, -4)
- C = (-4, -1)
- D = (-2, 3)
- E = (1, 3)
- F = (2, 5)
<u>Plot the points</u> on the coordinate plane (x, y) and connect them in alphabetical order with straight lines (see attached).
From visual inspection of the <u>drawn polygon</u>, we can see that the length of BC is 3 units.
It is fairly simple to calculate the length of BC without plotting the points.
As points B and C have the same x-value, this means that the distance between them is simply the difference between their y-values.
⇒ distance = |-4 - (-1)| = |-3| = 3 units
Answer:
1. No
2. Yes
3. No
Step-by-step explanation:
-4 is equal to -4 but not bigger then -4
8.5 is bigger then -4
-16 ¾ is smaler then -4
(because it is a negative number)
