Ans i trued
Step-by-step explanation:
Well, plug in all the values.
(sqrt)3>3
False. 3 would be more than it's square root.
(sqrt)9>3
3>3
This is false. 3 is not bigger than 3. They are equal.
(sqrt)15>3
3.8729..... >3
That is true,
(sqrt)10>3
3.1622>3
This true.
-3 and 0 would not work either.
So,
"C" and "D" are correct solutions.
I hope this helps!
~kaikers
The distance formula is the radical (x2-x1)2 + (y2-y1)^2. So for the x value, you subtract (-1) from 8. But be careful. It’s not 8-1. IT’S 8-(-1). Which x value, 9 should be squared. Which it is 81. The y value, you subtract 0 from 6. Which you should have 6 as your y value. Then, again you have to squared it. So, 6^2 is 36. Now that you have both of your x and y value, you have to subtract them again. In order to subtract, you subtract the y value from the x value. In other words, 81-36. The answer should be 45. But 45 is irrational. Because it can’t be rational under the radical form. So to simplified it, you have to find a number that is rational enough to get out from the inside of the radical form. The only number that would work is 9 and 5. So rad 9 is rational because it could escape from the inside. Which it’s 3 once it’s out. But, 5 is irrational and can’t go out. As a result, the answer is 3 rad 5. Or the 3 is outside of the radical form and 5 is the inside.
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + ( x + 2) = 267...combine like terms
3x + 3 = 267...subtract 3 from both sides
3x = 267 - 3
3x = 264
x = 264/3
x = 88
x + 1 = 88 + 1 = 89
x + 2 = 88 + 2 = 90
the largest will be 90
