All categories

3 years ago

You move down 1 units and up 2 units. You end at (-3,1). Where did you start? On a number graph 1 through 5 axis graph

Mathematics

1 answer:

Roman55 [17]3 years ago

6 0

Let's do it step by step:

First we need to understand that moving upwards would be addition to y-coordinates, while moving downwards would be deduction to the y-coordinates.

Moving to rightwards would be addition to x-coordinates and leftwards would be deduction to x-coordinates.

As we moved down by 1 unit and up for 2 units, it means that we are originally upward for one unit and downward by 2 units, which makes downwards for 1 units and would be -1 to the y-coordinates:

(-3,1 -1)

=(-3,0)

Therefore the start would be (-3,0).

Hope it helps!

You might be interested in

How many solutions does 0.75(x+40)=0.35(x+20)+0.35(x+20) have?

Neporo4naja [7]

Only one because there is one variable and the combined coefficients of x are non-zero.
(0.75(x+40)=0.70(x+20), 0.05x=14-30=-16, x=-320)

4 0

3 years ago

Read 2 more answers

Answer the 5 questions Listed below Please Show your Work

Zolol [24]

(6 1/3) / (5/6) = (19/3) / (5/6) = 19/3 * 6/5 = 114/15 = 38/5

3 - 7^2 + 3 * 4^2
3 - 49 + 3 * 16
3 - 49 + 48
- 46 + 48
2

(7b - 2) / (-a + 1)....a = -2, b = 3, c = -1/3
where is he c in this equation ? Because if I just use a and b, my answer is not an answer choice

(7b - 10) / (a - 1)...a = -1, b = 5, c = -2/3
same as before...where is the c in this equation

V = (pi) r^2* h
V = (pi)(5^2)(7)
V = (pi)(25)(7)
V = 175(pi)

5 0

3 years ago

Find the median for the scores 91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95, 72, 75

AnnyKZ [126]

$\huge\text{Hey there!}$

$\huge\textbf{What does \boxed{median} mean in math?}}$

$\boxed{\text{Median}}\rightarrow\textsf{ is the number in the middle.}$

$\huge\textbf{How do you find the \boxed{median}?}$

$\text{You can found it by putting the numbers from \bf least to greatest.}$

$\huge\textbf{Question reads....}$

$\text{Find the median for the scores 91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95,}\\\text{72, 75}$

$\huge\textbf{Equation:}$

$\text{91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95, 72, 75}$

$\huge\textbf{Rearrange the problems to:}$

$\text{69,71,71,71,72,74,75,82,87, 89,89,91,95,95}$

$\huge\textbf{The expression:}$

$\mathsf{\dfrac{75 + 82}{2} = median}$

$\huge\textbf{Simplify it:}$

$\mathsf{\dfrac{75 + 82}{2} = median}$

$\mathsf{\dfrac{157}{2} = median}$

$\mathsf{257\div2 = median}$

$\mathsf{78.5 = median}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{78.5}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>~ $\frak{Amphitrite1040:)}$ </h3>

8 0

1 year ago

64/143 - 21/208 what does it equal to and how?

Arlecino [84]

2 11/78 you just have to simply multiply 64/143 x2 because since it can't be subtracted. And after you multiply 64/143, you just have to subtract normally which is 128-21 and 286-208. Then since your answer came out to an improper fraction, so you have to simplify by dividing 107 divided by 78. Then you will get your answer which is 2 11/78.

5 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago