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3 years ago

10

I really need the answers please!

1 answer:

krek1111 [17]3 years ago

4 0

1) D = 13.6 g / mL

2)ethyl alcohol weighs 158g

3)ρ _copper = 8.9 g $cm^{3}$

Explanation:

1)

D = m / V

=306.0 g / 22.5 mL

D= 13.6 g / mL

2)

density = mass / volume

mass = density × volume

=0.789g /ml × 200.0 ml

M=158g

Ethyl alcohol weighs 158g

3)

ρ (density) = Mass / Volume

ρ _copper = 1896 g / 8.4cm × 5.5cm × 4.6cm

= 1896g / 212.5 $cm^{3}$

ρ _copper=8.9 g $cm^{3}$

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A sodium atom and sodium ion have the same

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<u>Answer:</u>

a) number of neutrons

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A sodium ion is formed when an electron is removed from a sodium atom. This means that the atom's number of electrons changes, but the number of neutrons remains unchanged.

However, as the number of electrons changes, the electric charge and the electronic structure change, which means that a sodium atom and a sodium ion do not have the same number of electrons, nor do they have the same electric charge or electronic structure.

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2 years ago

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3 years ago

A population of snails lives in a large field. As the size of the population grows, individual organisms on one side of the fiel

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3 years ago

Read 2 more answers

A bicycle completed the first 400.0 m of a ride in 86.8 s. What was the bicycle's average speed in kilometers per hour?

konstantin123 [22]

Answer:

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3 years ago

How many minutes will it take to plate out 2.19 g of chromium metal from a solution of Cr3+Cr3+ using a current of 55.2 amps in

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Answer : The time it take to plate out will be, 3.69 minutes.

Explanation :

First we have to calculate the moles of Cr.

$\text{Moles of }Cr}=\frac{\text{Mass of Cr}}{\text{Molar mass of Cr}}$

Molar mass of Cr = 51.9 g/mol

$\text{Moles of }Cr}=\frac{2.19g}{51.9g/mol}=0.0423mol$

The cathode half-reaction is,

$Cr^{3+}+3e^-\rightarrow Cr$

From this we conclude that,

The number of electrons (n) in the reaction are 3.

The quantity of charge required for the reduction of 1 mole of $Cr^{3+}$ = $3\times F$

The quantity of charge required for the reduction of 0.0423 mole of $Cr^{3+}$ = $0.0423\times 3\times F=0.1269F=0.1269\times 96500C=12245.85C$

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7 0

3 years ago