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2 years ago

Somebody please help meeeeeeeeee!! (The question is underneath the table)

Chemistry

1 answer:

Annette [7]2 years ago

6 0

Answer:

1.)

Parent 1:
Ff (genotype) and free earlobes (phenotype)

Parent 2:
ff (genotype) and attached earlobes (phenotype)

2.)

Ff and ff (possible genotypes)

Free earlobes and attached earlobes (possible phenotypes)

Explanation:

Phenotypes are the observable traits an organism displays.

Genotypes are the genetic sequences organisms' possess that code for particular traits.

I am assuming that heterozygous individuals (Ff) display the dominant trait (free earlobes). As such, one parent has the Ff genotype and the free earlobe phenotype. The other parent has the recessive genotype (ff) and phenotype (attached earlobe).

50% of the children will have the same genotype and phenotype of one parent and the other 50% will have the same genotype and phenotype as the other parent.

None of the children will have the completely dominant genotype (FF).

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How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10

Makovka662 [10]

Answer:

It takes 1.9 $\times 10^{6}$ years to distribute all the grains.

Explanation:

In one second, $10^{10}$ grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 $\times 10^{23}$

Number of grains distributed in 1 day = 86400 $\times 10^{10}$

= 8.64 $\times 10^{14}$

Number of grains distributed in 1 year= 8.64 $\times 10^{14} \times 365$

= 3.1536 $\times 10^{17}$

Time taken = $\frac{Number of grains to be distributed}{grains distributed in 1 year}$

= $\frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}$

= 1.9 $\times 10^{6}$

7 0

3 years ago

One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four ti

Arturiano [62]

The question is incomplete, the complete question is;

One tank of goldfish is feed the normal amount which is once a day, a second tank is fed twice a day, and a third tank is fed four times a day during a 6 week study. The fishes' body fat is recorded daily.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The amount of food the gold fish receives

B) Body fat of the gold fish

C) -Type of fish used in the study (gold fish)

Time period within which the fishes were fed (Six week period)

Shape and size of tank

D) group of gold fish fed the normal amount

Explanation:

The purpose of the study is to determined the impact of amount of feed on the body fat of gold fish. Hence, the amount of feed is the independent variable while the body fat of the feed is the dependent variable.

The control group receives the normal amount of feed (once a day). The fishes are all gold fish, fed within a six week period. All the tanks were of the same shape and size. These are the constants in the study.

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3 years ago

Helppp plsss !!!!!!!!!

geniusboy [140]

Answer:

B. because there is two equations just like commutative property in math its the same thingish

Explanation:

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3 years ago

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3 years ago

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