Answer:
0.107 mole of SO2.
Explanation:
1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).
With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.
This can be obtained as follow:
22.4 L contains 1 mole of SO2.
Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.
Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.
D - density: 13,534 g/ml
m - mass: 10g
V - volume: ??
_____________
d = m/V
V = m/d
V = 10/13,534
V = 0,7389 ml
:•)
<span>The solubilties of most ionic solids increase as the temperature increases.
Dissolving of a solid in water is, in most cases, an endothermic
reaction. In dissolving, as in melting, a solid becomes a liquid. It
takes more energy to be a liquid than to be a solid at the same
temperature. When the solution becomes saturated at any temperature, a
dynamic equilibrium is established between the dissolved and undissolved
solid. When heat is added that results in a higher temperature, the
extra heat favors the endothermic reaction, and more solid dissolves
rather than crystallizes until new equilibrium system is established
again. Hence, at a higher temperature, more solid is dissolved in
water. This increases the solid's solubility.
Hope this helps mate =)
</span>
ANSWER:
Group 18:
Elements are
-helium(He)
-neon (Ne)
-argon (Ar)
-krypton (Kr)
-xenon (Xe)
-radon (Rn)
-oganesson (Og)
Answer:
The answer to your question is P2 = 280 mmHg
Explanation:
Data
Pressure 1 = P1 = 400 mmHg
Volume 1 = V1 = 1.75 L
Pressure 2 = ?
Volume 2 = 2.5 L
Process
1.- Use Boyle's law to solve this problem
P1V1 = P2V2
-Solve for P2
P2 = P1V1 / V2
2.- Substitution
P2 = (400)(1.75) / 2.5
3.- Simplification
P2 = 700 / 2.5
4.- Result
P2 = 280 mmHg