Answer:
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Explanation:
The correct answer is option 2. Chlorine gas molecules are held together by strong covalent bonds. This type of bond requires an ample amount of energy in order to break it and turn gas into liquid. That is why, high pressure and low temperature is needed.
СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
<h3>Further explanation</h3>
Alkenes are unsaturated hydrocarbons that have a -C = C- double bond.
If there are 2 double bonds it is called an alkadiene, and if there are three double bonds it is called an alkatriene
General formula for Alkenes: CnH2n
addition reactions to alkenes follow Markovnikov's rule. in the addition reaction of hydrogen halide (HX), the halogen atom (X) will be bonded to the carbon atom that binds less H atom.
If the double-bonded carbon atom has the same number of H atoms attached to it, then the X atom will tend to be attached to the carbon atom with the longer alkyl group.
Addition reaction of propene compounds with HCl
СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
CH - this carbon atom binds fewer H atoms, so Cl is bonded to this bond
Answer:
A. 0.0655 mol/L.
B. PbBr2.
C. Pb2+(aq) + Br- --> PbBr2(s).
Explanation:
Balanced equation of the reaction:
Pb(NO3)2(aq) + 2NaBr(aq) --> PbBr2(s) + 2NaNO3(aq)
A.
Number of moles
PbBr2
Molar mass = 207 + (80*2)
= 367 g/mol.
Moles = mass/molar mass
= 3.006/367
= 0.00819 mol.
Since 2 moles of NaBr reacted to form 1 mole of PbBr2. Therefore, moles of NaBr = 2*0.00819
= 0.01638 moles of NaBr.
Since, the ionic equation is
NaBr(aq) --> Na+(aq) + Br-(aq)
Since 1 moles of NaBr dissociation in solution to give 1 mole of Br-
Therefore, molar concentration of Br-
= 0.0164/0.25 L
= 0.0655 mol/L.
B.
PbBr2
C.
Pb(NO3)2(aq)--> Pb2+(aq) + 2No3^2-(aq)
2NaBr(aq) --> 2Na+(aq) + 2Br-(aq)
Net ionic equation:
Pb2+(aq) + 2Br- --> PbBr2(s)
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