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BlackZzzverrR [31]
3 years ago
10

Na CO₂ (aq)+ CH3 COOH(aq) +​

Chemistry
2 answers:
babymother [125]3 years ago
6 0

Answer:

what are we doing......?????

NISA [10]3 years ago
4 0

Explanation:

CH3COOH + NaCO2 = CH3COONa + CO2 + H2O

chemical aid dot com

CH3 COOH(aq) is acetic acid or vinegar in water

NaCO2 is sodium carbonate or baking soda

CH3COONa is sodium acetate

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Find the mass in grams of 4.52
Tanzania [10]

Answer:

Mass = 1274 .64 g it would be option C if it is converted into kilogram

1274 .64 / 1000 = 1.27 Kg

Explanation:

Given data:

Number of moles of C₂₀H₄₂ = 4.52 mol

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.0 g/mol

Mass of C₂₀H₄₂ = ?

Solution:

Number of moles = mass / molar mass

Molar mass = 20× 12 + 42× 1.0 = 282 g/mol

Now we will put the values in formula:

Number of moles = mass / molar mass

4.52 mol = mass / 282 g /mol

Mass = 4.52 mol × 282 g/mol

Mass = 1274 .64 g

7 0
3 years ago
An analytical chemist is titrating 118.3 mL of a 0.3500 M solution of butanoic acid (HC3H7CO2) with a 0.400 M solution of KOH. T
TEA [102]

Answer:

pH = 12.33

Explanation:

Lets call HA = butanoic acid and A⁻ butanoic acid and its conjugate base butanoate respectively.

The titration reaction is

HA + KOH ---------------------------- A⁻ + H₂O + K⁺

number of moles of HA :   118.3 ml/1000ml/L x 0.3500 mol/L = 0.041 mol HA

number of  moles of OH  : 115.4 mL/1000ml/L x 0.400 mol/L  = 0.046 mol A⁻

therefore the weak acid will be completely consumed and what we have is  the unreacted strong base KOH which will drive the pH of the solution since the contribution of the conjugate base is negligible.

n unreacted KOH = 0.046 - 0.041 = 0.005 mol KOH

pOH = - log (KOH)

M KOH = 0.005 mol / (0.118.3 +0.1154)L = 0.0021 M

pOH = - log (0.0021) = 1.66

pH = 14 - 1.96 = 12.33

Note: It is a mistake to ask for the pH of the <u>acid solutio</u>n since as the above calculation shows we have a basic solution the moment all the acid has been consumed.

4 0
3 years ago
What is the correct name of the compound Mn3(PO4)2? A. manganese phosphate B. manganese(I) phosphate C. manganese(III) phosphate
Sergio039 [100]
The correct name of the compound Mn3(PO4)2 is  definitely the last option represented above <span>D. manganese(II) phosphate. I am pretty sure this answer will help you

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3 0
3 years ago
A covalent bond in which electrons are shared unequally is
tekilochka [14]
Covalent bonds = sharing of electrons between two atoms of the same elements or elements close to each other on the periodic table. Usually they are metals sometimes non-metals. In polar bonds electrons are shared unequally. Non polar bonds share electrons equally.


7 0
3 years ago
Write the chemical formula for the cation present in the aqueous solution of cuso4.
Inessa05 [86]

The ionic compounds on dissolving in aqueous solution dissociate into their respective ions that are cations and anions.

The ions present in the aqueous solution of CuSO_4 are Cu^{2+} and SO_{4}^{2-}.

So, the chemical formula of the cation present in the aqueous solution of CuSO_4 is Cu^{2+}.

4 0
3 years ago
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