Percentage composition of a compound is a ratio of an amount of each element to the total amount of individual elements in a compound, which is then multiplied with 100.
Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.
Explanation:
The statements that are true about 13C NMR are:
A. In 13C proton-decoupled NMR spectra, all peaks are singlets.
C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.
D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry
Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.
H2SO4(aq)+NaOH(s)----->NA2SO4 + H20
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is 2.08 atm.
<h3>What is the pressure?</h3>
In this problem, we are mandated to obtain the pressure both by the use of the ideal gas equation and then the use of the Van der Walls equation.
Using the idea gas equation;
PV = nRT
P = nRT/V
P = pressure
V = volume
n = number of moles
T = temperature
R = gas constant
P = 1 * 0.082 * (24 + 273)/0.5
P = 48.7 atm
Using the Van Der Wall equation:
P = RT/(V - b) - a /V^2
P = 0.082 * 297/(0.5 - 0.03219) - 1.345/(0.5)^2
P = 24.354/0.46781 - 1.345/ /0.25
P = 52 - 5.38
P = 46.62 atm
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is; 48.7 atm - 46.62 atm = 2.08 atm
Learn more about ideal gas equation:brainly.com/question/3637553
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Answer:
4.16x10⁻³m
Explanation:
Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.
As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.
<em>Moles glucose:</em>
There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.
Molar mass glucose:
6C = 12.01g/mol*6 = 72.06g/mol
12H = 12*1.008g/mol = 12.10g/mol
6O = 6*16g/mol = 96g/mol
72.06 + 12.10 + 96 = 180.16g/mol
Moles of 0.075g of glucose:
0.075g * (1 mol / 180.16g) =
4.16x10⁻⁴ moles of glucose
<em>Molality of the solution:</em>
4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =
<h3>4.16x10⁻³m</h3>
