Answer:
A typical atom consists of three subatomic particles: protons, neutrons, and electrons (as seen in the helium atom below). Other particles exist as well, such as alpha and beta particles (which are discussed below). The Bohr model shows the three basic subatomic particles in a simple manner. Most of an atom's mass is in the nucleus—a small, dense area at the center of every atom, composed of nucleons. Nucleons include protons and neutrons. All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.
Explanation:
The balanced chemical equation for the reaction is
<h3>6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g) </h3>
From the question given above, we were told that:
solid cesium reacts with solid cesium nitrite to form solid cesium oxide and nitrogen gas.
The equation for the reaction can be written as follow:
Caesium => Cs
Caesium nitrite => CsNO₂
cesium oxide => Cs₂O
nitrogen gas => N₂
Caesium + Caesium nitrite —> Caesium oxide + Nitrogen gas
<h3>Cs + CsNO₂ —> Cs₂O + N₂</h3>
The above equation can be balance as follow:
Cs + CsNO₂ —> Cs₂O + N₂
There are 2 atoms of N on the right side and 1 atom on the left side. It can be balance by writing 2 before CsNO₂ as shown below:
Cs + 2CsNO₂ —> Cs₂O + N₂
There are 2 atoms of Cs on the right side and a total 3 atoms on the left side. It can be balance by writing 6 before Cs and 4 before Cs₂O as shown below:
6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g)
Now the equation is balanced
Learn more: brainly.com/question/11502387
Equilibrium equation is
<span>Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) </span>
<span>From the reaction equation above, the formula for Ksp: </span>
<span>Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 </span>
<span>You know [CO32-], so you can solve for [Ag+] as: </span>
<span>(8.1 x 10^-12) = [Ag+]^2 (0.025) </span>
<span>[Ag+]^2 = 3.24 x 10^-10 </span>
<span>[Ag+] = 1.8 x 10^-5 M </span>
The gravitational force decreases
The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e
<h3>6.02×10²³ molecules = 1 mole of I₂</h3>
Recall:
1 mole of I₂ = 2 × 127 = 254 g
Thus,
<h3>6.02×10²³ molecules = 254 g of I₂</h3>
With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:
6.02×10²³ molecules = 254 g of I₂
Therefore,
2.57×10²⁵ molecules = 
<h3>2.57×10²⁵ molecules = 10843.52 g of I₂</h3>
Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
Learn more: brainly.com/question/24848191
