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KengaRu [80]
2 years ago
8

Calculate the bond length (in picometers) of a chemical bond between bromine and sulfur.

Chemistry
1 answer:
maria [59]2 years ago
7 0

The bond length of a chemical bond between bromine and sulfur is 216 picometers.

<h3>Explanation:</h3>
  • Bromine and sulfur reacts with each other to form Sulfur dibromide.
  • Sulfur dibromide is a covalent compound which means that a chemical bond exist between them is covalent bond.
  • So, for finding a bond length of a covalently bonded compound we need to add the covalent radiuses of the two atoms.

Given,

Covalent radius of bromine is 114 pm;

and  covalent radius of sulfur is102 pm.

∴  Bond length of the sulfur dibromide= Covalent radius of bromine +  covalent radius of sulfur

∴  Bond length = 114 + 102

∴  Bond length = 216 pm.

Learn more about Covalent bond here...

brainly.com/question/3447218

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Answer:

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Explanation:

We have the following data:

V = 50 L

P = 12.4 atm

T= 127°C + 273 = 400 K

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We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol

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A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine
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The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

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<h3>What mass of krypton tetrachloride can be produced assuming 100% yield?</h3>

Generally, the equation for ideal gas is mathematically given as

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n=0.441mol

Given the reaction

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Hence

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