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White raven [17]
3 years ago
13

The royal fruit company produces two types of fruit drinks the first type is 70% pure fruit juice and the second type is 95% pur

e fruit juice. the company is attempting to produce a fruit drink that contains 75% pure fruit juice how many pints of each of the two existing types of drinks must be used to make 60 pints of a make sure that is 75% pure fruit juice ?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0
This is a typical mixture problem where using a table is the best thing.
                 pints juice        % juice     =      total % juice
juice A            x                  .70          =        .70x
juice B        60-x                 .95          =    .95(60-x)
total              60                  .75          =    60(.75)

The last row gives you a total that you need to use, so do that multiplication to get 45. You now to need to add the last columns together for rows 1 and 2 and set them equal to 45: .7x +.95(60-x) = 45. When you do that math, you'll get that x = 48. This means that you need 48 pints of juice A and 60-48 pints of juice B, which is 12 pints.
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-2 from both sides

Step-by-step explanation:

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Answer:

C. Graph C

Step-by-step explanation:

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The graph that has length of bars that corresponds to the frequency of the colors is graph C

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A right triangle has a leg length of 21 inches and a hypotenuse length of 29 inches. What is the length of the other leg?​
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20

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4 0
3 years ago
How many centimeters are in a kilometer
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For 1 kilometer, it is 100,000 Centimeters. 
5 0
3 years ago
Read 2 more answers
The national vaccine information center estimates that 90% of americans have had chickenpox by the time they reach adulthood.50
timama [110]
Given:
 p = 90% = 0.9, the probability that an adult has had chickenpox by age 50.
Therefore,
q = 1 - p = 0.1, the probability that an adult has not had chickenpox by age 50.

Part (a)
Because there are only two answers: "Yes" or "No" to whether an adult has had chickenpox by age 50, the use of the binomial distribution is justified.

Part (b):
Calculate the probability that exactly 97 out of 100 sampled adults have had chickenpox.
The probability is
P₁ = ₁₀₀C₉₇ (0.9)⁹⁷ (0.1)³ = 0.0059

Answer: 0.006 or 0.6%

Part (c)
Calculate the probability that exactly 3 adults have not had chickenpox.
Theis probability is equal to 
P₂ = 1 - P₁ = 1 - 0.006 = 0.994

Answer: 0.994 or 99.4%

Part (d)
Calculate the probability that at least 1 out of 10 randomly selected adults have had chickenpox.
The probability is
P₃ = ₁₀C₀ (0.9)⁰ (0.1)¹⁰ + ₁₀C₁ (0.9)¹ (0.1)⁹ = 10⁻¹⁰ + 10⁻⁹ = 10⁻⁹ ≈ 0

Answer: 0

Part (e)
Calculate the probability that at most 3 out of 10 randomly selected adults have not had chickenpox.
The probability is
P₄ = 1 - [₁₀C₀ (0.9)⁰(0.1)¹⁰ + ₁₀C₁ (0.9)¹(0.1)⁹ + ₁₀C₂ (0.9)²(0.1)⁸ + ₁₀C₃ (0.9)³(0.1)⁷]
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     = 1

Answer:  1.0 or 100%

5 0
4 years ago
Read 2 more answers
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