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hjlf
2 years ago
5

A triangle has a base of x^1/2

Mathematics
1 answer:
Maksim231197 [3]2 years ago
4 0

Answer:

Base = 8 m

Height = 4 m

Step-by-step explanation:

Area of triangle

=  \frac{1}{2}  \times base \times height \\  \\  16 \times 2=   {x}^{ \frac{1}{2} }  \times  {x}^{ \frac{1}{3} }  \\  \\ 32 =  {x}^{ \frac{5}{6} }  \\  \\  {2}^{5} =  {x}^{ \frac{5}{6} }  \\  \\  ({2}^{2})^{ \frac{6}{5} }  = x \\  \\ x =  {2}^{5 \times  \frac{6}{5} }  \\  \\ x =  {2}^{6}  \\  \\ base =  {x}^{ \frac{1}{2} } =  {({2}^{6})}^{ \frac{1}{2} }  \\  \\  base =   {2}^{3}  \\  \\  base =   8 \: m \\  \\   \\ height =  {x}^{ \frac{1}{3} } =  {({2}^{6})}^{ \frac{1}{3} }  \\  \\  height=   {2}^{2}  \\  \\  height =   4 \: m

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Answer:

120

Step-by-step explanation:

Slope = rise / run

1/20 = 6 / run

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8 0
3 years ago
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Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
2 years ago
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Step-by-step explanation:

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Let Julio's normal hour rate is $x .

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31x +10*1.2x = 550.40
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43x= 550.40
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And this is reasonable , since working 41 hours at a rate of  $ 13 per hour is

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ArbitrLikvidat [17]

Step-by-step explanation:

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