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3 years ago

What is the mass of an object that has a volume of 16 ft^3 and a density of 4g/ft^3

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

m= v*d

m= 16.3*4.3

m=70.09 grams

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HELP PLEASE!! TON OF POINTS. RIGHT ANSWERS ONLY REWARDED. MATH GENIUSES?

Nonamiya [84]

Answer:

The graph is shifted 1 unit right

The graph is shifted 2 units down

Step-by-step explanation:

We are given

Parent function as

$f(x)=2^{x+3}-3$

New function as

$g(x)=2^{x+2}-1$

we can also write as

$g(x)=2^{x+3-1}-3+2$

We can see that

1 is subtracted to x-value

and 2 is added to y-value

So, f(x) is shifted right by 1 unit

and

f(x) is shifted up by 2 unit

3 0

3 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u /> $Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$