Answer:
45 minutes
Step-by-step explanation:
At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...
t = d/s
t = (7.5 mi)/(10 mi/h) = 0.75 h
to catch Peter.
Mitchell will catch Peter in 45 minutes.
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<em>Alternate Solution</em>
Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:
3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter
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You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.
It is 53°....................
The series 1022,1032,1042,1052....
a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term
Sn= a+(n-1)d
= 1022+(5-1)10
= 1022+40
= 1062
Next house will have 1062 as number.
Answer:
<h2>E. 22</h2>
Step-by-step explanation:
<em>Look at the picture</em>.
The lines <em>l</em> and <em>m</em> are parallel, therefore alternate interior angles are congruent.
Therefore 
Supplementary angles add up to 180°.
Therefore
<em>add 16 to both sides</em>
<em>subtract 5x from both sides</em>
We know: the sum of the triangle angle measures is 180°.
Therefore we have the equation:
