Answer:
(a) 110 mm Hg
(b) 70 mm Hg
(c) 3/4 second
(d) see the attachment
Step-by-step explanation:
(a) The sine function has a maximum value of +1, so the maximum value of p is ...
pmax = 20·(+1) +90 = 20+90 = 110 . . . . . mm Hg
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(b) The sine function has a minimum value of -1, so the minimum value of p is ...
pmin = 20·(-1) +90 = -20+90 = 70 . . . . . mm Hg
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(c) The period of the sine function is 2π, so the value of t that makes the argument be 2π will be the period.
8π/3·t = 2π
t = 2π·3/(8π) = 3/4 . . . . . . multiply by the inverse of the coefficient of t
The period of her heartbeat cycle is 3/4 seconds.
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(d) a graph is attached.
Answer:
B is P(x)=(x-3)^2 +2
C is P(x)=(x-1)^2 -5
Step-by-step explanation:
i think i am right
The square base area is 6 x 6 = 36. Then each triangle is the same base and height. Formula for area is 1/2(b)(h). So, each triangle is 1/2(6)(12)=36. So all sides are 36x5=180 units squared.
Answer:
Part 1
The mistake is Step 2: P + 2·x = 2·y
Part 2
The correct answer is
Step 2 correction: P - 2·x = 2·y
(P - 2·x)/2 = y
Step-by-step explanation:
Part 1
The student's steps are;
Step 1; P = 2·x + 2·y
Step 2: P + 2·x = 2·y
Step 3: P + 2·x/2 = y
The mistake in the work is in Step 2
The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y
Part 2
To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;
Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y
∴ P - 2·x = 2·y
(P - 2·x)/2 = y
y = (P - 2·x)/2
Step-by-step explanation:
Lets assume that angle of right angle trangles are <a,<b and <c
here one of the angle is 90°
so, <a=90°
now,
By the question
<c=3×<b+14
again,
<a+<b+<c=180° (being sum of interior angles of trangles)
90°+<b+(3×<b+14)=180° ( including the value of <a and <c)
90°+<b+3<b+14=180°
4<b=180-90-14
<b=86/4
<b=19°
<c=3×<b+14
=3×19+14
<c=71
smallest angle is 19°
and another small angle is 71°
