The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
First answer: 6 and 8
6 + 8 = 14
6 * 8 = 48
Second answer: 14 in the middle, 350 on top.
39 - 25 = 14
25 * 14 = 350
Let’s do 3x - 8 ≤ 23 first.
You need to rearrange this so that x is on its own.
+8 to both sides
3x ≤ 31
/3 on both sides
x ≤ 31/3
Then the second, -4x + 26 ≥ 6
-26 from both sides
-4x ≥ -20
/-4 on both sides
x ≥ 5
So x is greater than or equal to 5, which can also be written as 5 ≤ x
And for the first one, x is less than or equal to 31/3, which can still be written as x ≤ 31/3, so your final answer is:
5 ≤ x ≤ 31/3
Answer:
6 combinations
Step-by-step explanation:
Let
x----> the number of adult tickets
y---> the number of a child tickets
we know that
5x+3y=100 ----> linear equation that represent the situation
y=-(5/3)x+(100/3)
The maximum number of adult tickets is 20 (20*$5=$100)
The maximum number of a child tickets is 33 (33*$3=$99)
Construct a table for different values of x and find the values of y
The possible combinations will be pairs of whole numbers
see the attached table
The solution is 6 combinations
Answer:
yes!!
Step-by-step explanation: