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shtirl [24]
3 years ago
7

Find the median of the following numbers: 195, 230, 200, 226​

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer: 213

Step-by-step explanation: The median is the middle number

in the data set when the data set is written from least to greatest.

So let's start with writing ur data set from least to greatest.

So we have 195, 200, 226, 230.

Notice that there are two middle numbers.

If there are two middle numbers in the data set,

we find the median by taking their average.

In other words, we add the two middle numbers and divide by two.

So we have 200 + 226/2 or 426/2 which is 213.

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=(2y-3)(y-2)
Therefore
y=3/2 or y=2
3 0
3 years ago
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Keith_Richards [23]

Answer:

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Step-by-step explanation:

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3 years ago
W = 1/2QV if w=.47 and v=13.5
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8 0
3 years ago
The members of a high school band asked a number of students whether they would like blue, gold, or both for the uniforms for th
MaRussiya [10]

The values of a and b are a = 33% and b = 43% ⇒ last answer

Step-by-step explanation:

The venn-diagram contains:

  • A circle labeled blue 32
  • A circle labeled gold 25
  • The two circles are overlap with label 12 on the overlap

The table:

→ Band  :  blue  :  N.b  : total

→ gold   :  16%   :  a      :  49%

→ N.g     :  b       :  8%   :  51%

→ Total  :  59%  :  41%  :  100%

We need to find the values of a and b

From the table

16% represents the percentage of blue and gold uniforms (2nd row with 2nd column)

From venn-diagram

The common part of blue and gold label with 12 (overlap of two circles)

∴ 16% of the total number of students = 12

∵ 16% × x = 12

∴ \frac{16}{100} × x = 12

∴ 0.16 x = 12

- Divide both sides by 0.16

∴ x = 75

∵ x represents the total number of students

∴ The total number of students were asked is 75

From the table

b represents the percentage of blue but not gold uniforms (3rd row and 2nd column)

From venn-diagram

The part that has blue and not gold labeled with 32 (the part of the blue circle not in the gold circle)

∴ 32 of the total number of students like the blue but not gold

- Divide 32 by the total 75 , then multiply the quotient by 100%

   to find the percentage of blue but not gold

∴ b = \frac{32}{75} × 100% = 42.6666%

∴ b ≅ 43%

From the table

a represents the percentage of gold nut not blue uniforms (2nd row and 3rd column)

From venn-diagram

The part that has gold and not blue labeled with 25 (the part of the gold circle not in the blue circle)

∴ 25 of the total number of students like the gold but not blue

- Divide 25 by the total 75 , then multiply the quotient by 100%

   to find the percentage of gold but not blue

∴ a = \frac{25}{75} × 100% = 33.3333%

∴ a ≅ 33%

The values of a and b are a = 33% and b = 43%

To check your answer complete the table you will find the total of it is 100% ( for the columns 16% + 43% = 59% , 33% + 8% = 41% , then 59% + 41% = 100%, for the rows 16% + 33% = 49% , 43% + 8% = 51% , then 49% + 51% = 100%)

Learn more:

You can learn more about the probability in brainly.com/question/3756853

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share? (1 point) A ri
dlinn [17]

Answer:

m 36.606

Step-by-step explanation:

90*sin24

90*0.406

is equal to 36.606

approximately 37

5 0
2 years ago
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