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3 years ago

Factor the following, I will give 5 stars and thanks.

Mathematics

1 answer:

tigry1 [53]3 years ago

5 0

Answer:

13) $n=-3,-7$

14) $b=-4,-8$

15) $m=-7$

16) $a=-5,-7$

Step-by-step explanation:

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In a random sample of 300 people in a town, 193 were female. What is the sample portion of female

Inessa [10]

Answer: 0.643

Step-by-step explanation:

There are 300 people and 193 were female.

The sample portion that is female is therefore;

= 193/300

= 0.643

3 0

3 years ago

لان

Mandarinka [93]

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3 years ago

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svetoff [14.1K]

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3 years ago

Read 2 more answers

Describe how (2^3)(2^-4) can be simplifed

yanalaym [24]

Answer:

$2^3\times2^{-4}=\frac{1}{2}$

Step-by-step explanation:

The given expression is

$(2^3)(2^{-4})$

This is the same as;

$2^3\times2^{-4}$

Recall that;

$a^m\times a^n=a^{m+n}$

This implies that;

$2^3\times2^{-4}=2^{3+-4}$

$2^3\times2^{-4}=2^{-1}$

We now use the following law of exponents

$a^{-m}=\frac{1}{a^m}$

This gives us;

$2^3\times2^{-4}=\frac{1}{2}$

7 0

3 years ago

Complete the statement by filling in the blanks: When constructing a confidence interval, if the level of confidence increases,

Yuki888 [10]

Answer:

$\hat p \pm z_{\alpha/2} SE_{\hat p}$

And for this case the margin of error would be:

$ME= z_{\alpha/2} SE_{\hat p}$

If the level of confidence increase we can conclude that the value of $z_{\alpha/2}$ would increase and the the confidence interval would be wider, since the margin of error increase.

c. Increase; wider

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let's assume that we have a parameter of interest $p$ and we want to estimate the value of p with $\hat p$ and in general the confidence interval if the distribution of p is normal is given by:

$\hat p \pm z_{\alpha/2} SE_{\hat p}$

And for this case the margin of error would be:

$ME= z_{\alpha/2} SE_{\hat p}$

If the level of confidence increase we can conclude that the value of $z_{\alpha/2}$ would increase and the the confidence interval would be wider, since the margin of error increase.

c. Increase; wider

8 0

3 years ago