All categories

2 years ago

Factor the following, I will give 5 stars and thanks.

Mathematics

1 answer:

tigry1 [53]2 years ago

5 0

Answer:

13) $n=-3,-7$

14) $b=-4,-8$

15) $m=-7$

16) $a=-5,-7$

Step-by-step explanation:

You might be interested in

Ida is cutting a 11/12 foot wooden board into 3/16 foot sections to do some detail work on a model she is building. How many who

zlopas [31]

You have to give them the same denominator so multiply 11/12 by 4 and 3/16 by 3. giving you 44/48 and 9/48. then divied 44 by 9 giving you 4.8888
there for there are 4 whole 3/16 sections of the 11/12 board

3 0

3 years ago

Read 2 more answers

The scatter plot below shows the distances some employees of a company commute to work and the annual

salantis [7]

Answer:

It is a

Step-by-step explanation: I looked it up

6 0

3 years ago

True or false? a triangle can be circumscribed about a given circle

Sphinxa [80]

Answer:\

The answer to you is:

True

7 0

3 years ago

1000 is 1/10 of what number?

Gekata [30.6K]

Answer:

10,000

Step-by-step explanation:

1000x10=

10000

8 0

2 years ago

Read 2 more answers

A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

8 0

3 years ago