Answer:
Part 1:
Answer is in first photo below
Part 2:
Answer is in second photo below
I hope this helps!
The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
(A) Mitochondria, I believe.
The answer is a carrying capacity.
The carrying capacity is the maximum size of some population, for example, wolves population, that can survive in the given environment, in this case, the forest. It represents the number of animals that can live, reproduce, survive in the given area regarding the indefinite sustainability of this area in terms of resources (food, water, habitat, etc.)
Answer:
abrasion
Explanation:its another word for erosion
