Answer:
The answer w'll be obtained using formulas
cos(a+b) = cosacosb - sinasinb
cos(a-b) = cosacosb + sinasinb
Step-by-step explanation:
Using the trigonometric formula of addition and subtraction of cosine
cos(a+b) = cosacosb - sinasinb
cos(a-b) = cosacosb + sinasinb
w'll get the desired answer.
To be solve
L.H.S = R.H.S
sinasinb = (cos(a-b)-cos(a+b)/2
as we know that <u><em>cos(a+b) = cosacosb - sinasinb</em></u>
sinasinb = (cos(a-b) - (cosacosb -sinasinb))/2
as we know that <u><em>cos(a-b) = cosacosb + sinasinb</em></u>
sinasinb = ((cosacosb + sinasinb) - (cosacosb -sinasinb))/2
sinasinb = (cosacosb + sinasinb - cosacosb + sinasinb)/2
sinasinb = (2sinasinb)/2
sinasinb = sinasinb
hence L.H.S = R.H.S
<span>if its 3 times (6/8 − 1/2) + 0.25 then this equals 1
if its </span><span>3x(6/8 − 1/2) + 0.25 then its 3/4x+1/4</span>
Since x is our unknown number, on one side of our equation we will have the "<span>Subtracting two times a number from 10", and on the other will be -3. So,
-3=10-2x</span>
What would you like me to draw and label?
There is no image, what does that mean?
